Calculating Total Cleared Candidates in State A (2016-2020)

The question asks us to find the total number of students who successfully cleared the university entrance examination from State A over the years 2016 to 2020. The provided table gives us two pieces of information for each state and year:

• N: The number of candidates appearing for the exam, in lakhs.
• P(%): The percentage of candidates who cleared the exam.

To find the number of candidates who cleared the exam in a particular year for State A, we need to calculate P% of N. Since N is given in lakhs, we first convert N into the actual number of candidates by multiplying it by 100,000. Then, we multiply this number by the percentage of candidates who cleared (P/100).

Step-by-Step Calculation for State A (2016-2020)

Let's calculate the number of cleared candidates for State A for each year:

• Year 2016:
  Number appearing (N) = 2.3 lakhs = $2.3 \times 100,000 = 230,000$
  Percentage clearing (P) = 13%
  Number cleared = $230,000 \times \frac{13}{100} = 230,000 \times 0.13 = 29,900$
• Year 2017:
  Number appearing (N) = 2.02 lakhs = $2.02 \times 100,000 = 202,000$
  Percentage clearing (P) = 44%
  Number cleared = $202,000 \times \frac{44}{100} = 202,000 \times 0.44 = 88,880$
• Year 2018:
  Number appearing (N) = 1.98 lakhs = $1.98 \times 100,000 = 198,000$
  Percentage clearing (P) = 39%
  Number cleared = $198,000 \times \frac{39}{100} = 198,000 \times 0.39 = 77,220$
• Year 2019:
  Number appearing (N) = 1.85 lakhs = $1.85 \times 100,000 = 185,000$
  Percentage clearing (P) = 28%
  Number cleared = $185,000 \times \frac{28}{100} = 185,000 \times 0.28 = 51,800$
• Year 2020:
  Number appearing (N) = 2.20 lakhs = $2.20 \times 100,000 = 220,000$
  Percentage clearing (P) = 33%
  Number cleared = $220,000 \times \frac{33}{100} = 220,000 \times 0.33 = 72,600$

Total Cleared Candidates (2016-2020) in State A

To find the total number of students who cleared the entrance exam from 2016 to 2020 in State A, we sum the number of cleared candidates for each year:

Total Cleared = (Cleared in 2016) + (Cleared in 2017) + (Cleared in 2018) + (Cleared in 2019) + (Cleared in 2020)

Total Cleared = $29,900 + 88,880 + 77,220 + 51,800 + 72,600$

Summing these yearly numbers gives the total number of cleared candidates for State A from 2016 to 2020.

Total Cleared = $364,420$

Therefore, the total number of students who have cleared the entrance exam from 2016 to 2020 in State A is 364,420.

Revision Table: State A Exam Data

Additional Information: Understanding Data Interpretation Tables

Data interpretation questions often require extracting information from tables, charts, or graphs and performing calculations based on that data. For tables like the one provided, it's crucial to understand the units used (like 'lakhs' for candidate numbers) and how percentages apply to the base number.

Key steps in solving table-based data interpretation problems:

• Read the question carefully to understand exactly what is being asked (e.g., total over years, average, ratio, difference, data for a specific state or year).
• Identify the relevant rows and columns in the table needed to answer the question.
• Pay attention to the units of measurement (e.g., thousands, lakhs, millions) and convert if necessary for calculations.
• Understand the relationship between different columns (e.g., how percentage clearing relates to the number of appearing candidates).
• Perform the necessary calculations (addition, subtraction, multiplication, division, percentage calculations, averages, ratios).
• Double-check your calculations to avoid errors.

This question specifically involved calculating the number of candidates who cleared the exam in State A for each year and then summing these yearly totals to find the cumulative number over five years.