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Question

Study the table and answer the following questions based on it.

The following table gives the percentage of marks obtained by 7 students in 5 different subjects in an examination. (The maximum marks in a subject is 100.)

Sub 1Sub 2Sub 3Sub 4Sub 5
Student 14045556570
Student 26070756560
Student 37074646872
Student 45075576562
Student 56166725860
Student 67065685678
Student 76545705258

Find out the percentage of students, whose average marks is more than 60%.

The correct answer is

65.64

Understanding the Problem: Analyzing Student Marks

The question asks us to analyze the provided table showing the percentage marks obtained by 7 students across 5 different subjects. The maximum marks for each subject is 100, meaning the values in the table are directly the percentage scores.

We need to find out a specific percentage related to students whose average marks exceed 60%.

Let's first look at the data presented in the table:

Sub 1 Sub 2 Sub 3 Sub 4 Sub 5
Student 1 40 45 55 65 70
Student 2 60 70 75 65 60
Student 3 70 74 64 68 72
Student 4 50 75 57 65 62
Student 5 61 66 72 58 60
Student 6 70 65 68 56 78
Student 7 65 45 70 52 58

Calculating Average Marks for Each Student

To find the average marks for each student, we need to sum up their marks in all 5 subjects and divide by the number of subjects, which is 5.

The formula for average marks is:

\( \text{Average Marks} = \frac{\text{Sum of marks in all subjects}}{\text{Number of subjects}} \)

Let's calculate the average for each of the 7 students:

  • Student 1: \( (40 + 45 + 55 + 65 + 70) / 5 = 275 / 5 = 55\% \)
  • Student 2: \( (60 + 70 + 75 + 65 + 60) / 5 = 330 / 5 = 66\% \)
  • Student 3: \( (70 + 74 + 64 + 68 + 72) / 5 = 348 / 5 = 69.6\% \)
  • Student 4: \( (50 + 75 + 57 + 65 + 62) / 5 = 309 / 5 = 61.8\% \)
  • Student 5: \( (61 + 66 + 72 + 58 + 60) / 5 = 317 / 5 = 63.4\% \)
  • Student 6: \( (70 + 65 + 68 + 56 + 78) / 5 = 337 / 5 = 67.4\% \)
  • Student 7: \( (65 + 45 + 70 + 52 + 58) / 5 = 290 / 5 = 58\% \)

Here is a summary of the average marks for each student:

  • Student 1: 55%
  • Student 2: 66%
  • Student 3: 69.6%
  • Student 4: 61.8%
  • Student 5: 63.4%
  • Student 6: 67.4%
  • Student 7: 58%

Identifying Students with Average Marks > 60%

Now we need to identify the students whose average marks are more than 60%.

  • Student 1: 55% (Not > 60%)
  • Student 2: 66% ( > 60%)
  • Student 3: 69.6% ( > 60%)
  • Student 4: 61.8% ( > 60%)
  • Student 5: 63.4% ( > 60%)
  • Student 6: 67.4% ( > 60%)
  • Student 7: 58% (Not > 60%)

The students whose average marks are more than 60% are Student 2, Student 3, Student 4, Student 5, and Student 6.

There are 5 students with average marks greater than 60%.

Calculating the Required Percentage

The question asks for a percentage related to these students. Based on the wording "percentage of students, whose average marks is more than 60%", the most direct interpretation is the percentage of the total number of students who meet this criterion.

Number of students with average > 60% = 5

Total number of students = 7

Percentage of students with average > 60% \( = \frac{\text{Number of students with average > 60%}}{\text{Total number of students}} \times 100 \)

\( = \frac{5}{7} \times 100 \approx 71.428...\% \)

This percentage is approximately 71.43%. However, this value is not among the given options (55, 65.64, 85.7, 63.4).

Given the options, it is possible that the question intends for a different calculation. Let's consider another possible interpretation based on the provided options. One of the options is 65.64.

Let's examine the average marks of the students who scored more than 60%:

Students with average > 60%: 66%, 69.6%, 61.8%, 63.4%, 67.4%.

Let's calculate the average of these average marks:

\( \text{Average of Averages} = \frac{66 + 69.6 + 61.8 + 63.4 + 67.4}{5} \)

\( = \frac{328.2}{5} \)

\( = 65.64\% \)

This value, 65.64%, matches one of the options provided.

Therefore, it appears the question might be asking for the average of the average marks obtained by the students who scored more than 60% overall.

Conclusion on Student Performance Analysis

While the phrasing of the question typically implies finding the percentage of students meeting a condition, the calculation leading to one of the provided options (65.64) is the average of the average marks of the students whose individual average marks are greater than 60%. Following this calculation, we find the value 65.64.

Revision Table: Key Calculations

Student Sum of Marks Average Marks (%) Average > 60%?
Student 1 275 55 No
Student 2 330 66 Yes
Student 3 348 69.6 Yes
Student 4 309 61.8 Yes
Student 5 317 63.4 Yes
Student 6 337 67.4 Yes
Student 7 290 58 No

Students with average > 60%: Student 2, 3, 4, 5, 6. (5 students)

Average of their averages: \( \frac{66 + 69.6 + 61.8 + 63.4 + 67.4}{5} = \frac{328.2}{5} = 65.64 \)

Additional Information: Data Interpretation Tips

Data interpretation questions often involve analyzing tables, charts, or graphs to extract information and perform calculations. Key skills for these questions include:

  • Carefully reading the question and understanding exactly what is being asked.
  • Extracting relevant data from the source (table, chart, etc.).
  • Performing calculations accurately (sums, averages, percentages, ratios, etc.).
  • Being mindful of units and what the numbers represent (e.g., raw scores, percentages).
  • Considering all options if a calculated value doesn't match, and re-evaluating the question or calculation method if necessary.
  • Practice with different types of data representations helps improve speed and accuracy.
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Important Questions from Tabulation

  1. The table shows District-wise data of a number of primary school teachers posted in schools of a city.

    Study the table and answer the question:

    District

    Male teachers

    Female teachers

    East

    1650

    2375

    North

    1075

    2651

    West

    1280

    1520

    South

    1170

    1085

    Central

    690

    859


    What is the difference between the total number of male teachers in the districts East, North, West taken together and the total number of female teachers in the districts East and South?
  2. Table shows income (in Rs. ) received by 4 employees of a company during the month of December 2020 and all their income sources.

    Source

    Amit

    Suresh

    Nitin

    Varun

    Salary

    35000

    38500

    29000

    42000

    Arrears

    6000

    6300

    5000

    7500

    Bonus

    1000

    1100

    1000

    1240

    Overtime

    1800

    1950

    1400

    1500


    What is the ratio of salary of Varun to his income other than salary?
  3. Study the table and answer the question:

    Income (Rs.)

    No. of persons

    Less than 200

    12

    Less than 250

    26

    Less than 300

    34

    Less than 350

    40

    Less than 400

    50


    What is the percentage of persons earning Rs. 250 or more?
  4. The following table shows the annual profit of a company (in Rs. lakh).

    2014-2015

    2015-2016

    2016-0217

    2017-2018

    2018-2019

    625

    690

    725

    775

    815

    The period which has the maximum percentage increase in profit over the previous year is:

  5. The table given below shows the number of persons participating in a survey from 6 different states.

    States Persons 
    S1100
    S2200 
    S3400 
    S4500 
    S5600 
    S6800

    What is the ratio of number of person participating in a survey from state S3 to the number of person participating in a survey from state S4?

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