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Question

Figure shows a rectangular conductor PQRS in which the conductor PQ is free to move. The conductor PQ is moved towards the left with a constant velocity V as shown in the figure. Assume that there is no loss of energy due to friction.
What will be the magnetic flux linked with the loop PQRS and the motional emf?

The correct answer is
Magnetic flux = Blx; Motional emf = BIV

To solve the problem regarding the rectangular conductor PQRS with the conductor PQ moving with a constant velocity \( V \), we need to find the magnetic flux linked with the loop and the motional emf.

Concept Used: The magnetic flux (\(\Phi\)) through a surface is given by:

\(\Phi = B \times A\)

where \( B \) is the magnetic field and \( A \) is the area of the surface. For a rectangle, \( A = l \times x \) where \( l \) is the length and \( x \) is the distance moved.

The motional emf (\(\varepsilon\)) induced in a conductor moving in a magnetic field is given by:

\(\varepsilon = B \times l \times V\)

where \( V \) is the velocity of movement.

  1. Calculate the Magnetic Flux:
    • The area \( A = l \times x \).
    • Thus, the magnetic flux \(\Phi = B \times (l \times x) = Blx\).
  2. Calculate the Motional EMF:
    • The motional emf as derived from the formula is \(\varepsilon = B \times l \times V\).

By using the above considerations, the correct answer is:

  • Magnetic flux = \(Blx\)
  • Motional emf = \(BIV\)

Thus, the option Magnetic flux = Blx; Motional emf = BIV is correct.

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Important Questions from Electromagnetic Induction

  1. The half-life period of a radioactive element 'X' is same as the mean life of another radioactive element Y. Initially both of them have the same no. of atoms, then:

    A. X and Y have the same decay rate initially.

    B. X and Y decay at the same rate always.

    C. Y will decay at a faster rate than X.

    D. X will decay at a faster rate than Y.

    Choose the correct answer from the options given below:

  2. The wire loop PQRSP formed by joining two semicircular wires of radii R1 & R2 carries a current I as shown in the figure. The magnitude of the magnetic field at the centre 'C' is:

  3. A Neutron is moving with a velocity of V in a non-uniform magnetic field as shown in the figure.

    Velocity of neutron would be:

  4. The graph between resistivity and temperature given below can be for the material:

  5. Which phenomenon proves the particle nature of photons?

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