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Question

Express $5.97\bar3$ as a vulgar fraction.

The correct answer is
$5\frac{219}{225}$

Converting Repeating Decimal to Fraction

To express the repeating decimal $5.97\bar3$ as a vulgar fraction, we follow these steps:

  • Let the given number be $x$. So, $x = 5.97333...$
  • Multiply $x$ by 100 to move the decimal point just before the repeating part starts:

    $100x = 597.333... \quad (1)$

  • Multiply $x$ by 1000 to move the decimal point one place after the start of the repeating digit:

    $1000x = 5973.333... \quad (2)$

  • Subtract equation (1) from equation (2) to eliminate the repeating decimal part:

    $1000x - 100x = 5973.333... - 597.333...$

    $900x = 5376$

  • Solve for $x$:

    $x = \frac{5376}{900}$

  • Simplify the fraction. Both numerator and denominator are divisible by 4:

    $x = \frac{5376 \div 4}{900 \div 4} = \frac{1344}{225}$

  • The fraction $\frac{1344}{225}$ can be further simplified by dividing by 3 (since $1+3+4+4=12$ and $2+2+5=9$, both divisible by 3):

    $x = \frac{1344 \div 3}{225 \div 3} = \frac{448}{75}$

  • Convert the improper fraction $\frac{448}{75}$ into a mixed number. Divide 448 by 75:

    $448 \div 75 = 5 \text{ with a remainder of } 448 - (5 \times 75) = 448 - 375 = 73$

    So, $x = 5\frac{73}{75}$.

Matching with Options

Now, let's check the given options:

  • Option A: $5\frac{219}{225}$. To check if this equals $5\frac{73}{75}$, simplify the fractional part $\frac{219}{225}$. Both are divisible by 3:

    $\frac{219 \div 3}{225 \div 3} = \frac{73}{75}$

    Thus, $5\frac{219}{225} = 5\frac{73}{75}$.

Therefore, the correct representation of $5.97\bar3$ as a vulgar fraction is $5\frac{219}{225}$.

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Important Questions from Fractions

  1. Which fraction among the following is the least ?

    \(\frac{5}{11}, \frac{7}{12}, \frac{8}{13}, \frac{9}{17}\)

  2. Find the value of the following expression:

    \(\frac{{3 \div 1 \times 2 + 5 - 2}}{{3 \times 3 - 2}}\)

  3. Simplify the expression 441 ÷  \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)

  4. If the sum of two positive numbers is 65 and the square root of their product is 26, then the sum of their reciprocals is:

  5. The value of \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\)  is:

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