Evaluate $5.29 \bar{8} - 6.29 \bar{8} + 7.29 \bar{8} $
The problem asks us to evaluate the expression involving repeating decimals: $5.29\bar{8} - 6.29\bar{8} + 7.29\bar{8}$. To solve this, we will convert each repeating decimal into its equivalent fraction and then perform the subtraction and addition.
A repeating decimal is a decimal number that has a digit or a sequence of digits that repeat infinitely. We can convert these into fractions using an algebraic method.
$1000x - 100x = 5298.\bar{8} - 529.\bar{8}$
$900x = 4769$
$x = \frac{4769}{900}$
Using the same method:
$1000y - 100y = 6298.\bar{8} - 629.\bar{8}$
$900y = 5669$
$y = \frac{5669}{900}$
Again, applying the same steps:
$1000z - 100z = 7298.\bar{8} - 729.\bar{8}$
$900z = 6569$
$z = \frac{6569}{900}$
Now substitute the fractional equivalents back into the original expression:
$5.29\bar{8} - 6.29\bar{8} + 7.29\bar{8} = x - y + z$
$= \frac{4769}{900} - \frac{5669}{900} + \frac{6569}{900}$
Since the denominators are the same, we can combine the numerators:
$ \frac{4769 - 5669 + 6569}{900} $
$ \frac{-900 + 6569}{900} $
$ \frac{5669}{900} $
The result of the evaluation $5.29\bar{8} - 6.29\bar{8} + 7.29\bar{8}$ is $\frac{5669}{900}$.
If + means -, - means $\times$, $\times$ means $\div$ and $\div$ means +, then what will come in place of the question mark (?) in the following equation?
$29+14\times7\div11-9=?$
A car travels $\frac{1}{4}$th of the distance at a speed of 60 km/hr and the remaining $\frac{3}{4}$th of the distance at a speed of $v$ km/hr. If the average speed for the full journey is 50 km/hr, then the value of $v$ is