Electromagnetic wave in order of longest to shortest wavelength
A. Microwave
B. Radio wave
C. Visible light
D. Ultraviolet
E. Infrared
Choose the correct answer from the options given below:
The electromagnetic spectrum includes various types of radiation, all traveling at the speed of light but differing in their wavelength and frequency. Understanding the order of these waves based on their wavelength is a fundamental concept in physics.
Electromagnetic waves are characterized by their wavelength ($\lambda$), which is the distance between successive crests of a wave. Wavelength is inversely proportional to frequency ($f$), described by the equation $\lambda = \frac{c}{f}$, where $c$ is the speed of light. This means waves with longer wavelengths have lower frequencies, and waves with shorter wavelengths have higher frequencies.
The question asks us to arrange specific electromagnetic waves in order of their wavelength, starting from the longest wavelength and moving towards the shortest.
The electromagnetic spectrum, in order of decreasing wavelength (and increasing frequency), is typically presented as follows:
Radio waves > Microwaves > Infrared radiation > Visible light > Ultraviolet radiation > X-rays > Gamma rays.
We are given the following electromagnetic waves:
Using the standard order of the electromagnetic spectrum, we can determine the relative wavelengths of the given waves:
This places them in the following order from longest wavelength to shortest wavelength:
| Order | Wave Type | Letter | Relative Wavelength |
|---|---|---|---|
| 1 (Longest) | Radio wave | B | Longest |
| 2 | Microwave | A | |
| 3 | Infrared | E | |
| 4 | Visible light | C | |
| 5 (Shortest) | Ultraviolet | D | Shortest |
Therefore, the correct sequence of the electromagnetic waves from longest wavelength to shortest wavelength is B, A, E, C, D.
This sequence correctly orders the electromagnetic waves as requested.
The correct order of electromagnetic spectrum with decreasing frequency is:
The value of the proportionality constant μo/(4π) is equal to _________ Tm/A.
Match List I with List II
List – I | List – II | ||
US New Military Bands for Microwaves | Frequency range in GHz | ||
A. | H band | I. | 2.000 ‐ 3.000 GHz |
B. | J band | II. | 4.000 ‐ 6.000 GHz |
C. | G band | III. | 6.000 ‐ 8.000 GHz |
D. | E band | IV. | 10.000 ‐ 20.000 GHz |
Choose the correct answer from the options given below:
The wave number of the limiting line of the series (visible) in hydrogen spectrum is: