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Question

An electromagnetic wave propagates through a linear, isotropic, and homogeneous material medium.
If this medium has a relative permittivity of $\varepsilon_r$ and a relative permeability of $\mu_r$, and the speed of light in vacuum is $c$, what is the ratio of the speed of the electromagnetic wave in the medium ($v$) to its speed in vacuum ($c$)?

The correct answer is
$\frac{1}{\sqrt{\varepsilon_r \mu_r}}$

Understanding Electromagnetic Wave Propagation in a Medium

This question asks about the speed of an electromagnetic wave as it travels through a specific type of material. We need to find the ratio of its speed in this material (denoted by $v$) compared to its speed in a vacuum (denoted by $c$). The material is described as linear, isotropic, and homogeneous, and we are given its relative permittivity ($\varepsilon_r$) and relative permeability ($\mu_r$).

Speed of Light Formulas

Let's recall the fundamental formulas for the speed of light:

  • The speed of light in a vacuum, $c$, is a fundamental constant related to the permeability of free space ($\mu_0$) and the permittivity of free space ($\varepsilon_0$) by the equation: $c = \frac{1}{\sqrt{\mu_0 \varepsilon_0}}$
  • The speed of an electromagnetic wave in a material medium, $v$, depends on the medium's absolute permeability ($\mu$) and absolute permittivity ($\varepsilon$): $v = \frac{1}{\sqrt{\mu \varepsilon}}$

Relating Medium Properties to Vacuum Properties

The question provides the relative properties of the medium:

  • Relative permittivity ($\varepsilon_r$): This tells us how the electric field properties of the medium compare to a vacuum. It's defined as $\varepsilon_r = \frac{\varepsilon}{\varepsilon_0}$. Therefore, the permittivity of the medium is $\varepsilon = \varepsilon_r \varepsilon_0$.
  • Relative permeability ($\mu_r$): This tells us how the magnetic field properties of the medium compare to a vacuum. It's defined as $\mu_r = \frac{\mu}{\mu_0}$. Therefore, the permeability of the medium is $\mu = \mu_r \mu_0$.

Since the medium is linear, isotropic, and homogeneous, these relative values are constant.

Calculating the Speed in the Medium ($v$)

We can substitute the expressions for $\mu$ and $\varepsilon$ into the formula for $v$:

$v = \frac{1}{\sqrt{(\mu_r \mu_0) (\varepsilon_r \varepsilon_0)}}$

Rearranging the terms under the square root:

$v = \frac{1}{\sqrt{\mu_r \varepsilon_r \mu_0 \varepsilon_0}}$

We can separate this expression:

$v = \left( \frac{1}{\sqrt{\mu_r \varepsilon_r}} \right) \left( \frac{1}{\sqrt{\mu_0 \varepsilon_0}} \right)$

Recognizing that the second part is the speed of light in vacuum, $c$:

$v = \frac{1}{\sqrt{\varepsilon_r \mu_r}} c$

Finding the Ratio $v/c$

To find the required ratio, we divide the expression for $v$ by $c$:

$\frac{v}{c} = \frac{\frac{1}{\sqrt{\varepsilon_r \mu_r}} c}{c}$

The $c$ terms cancel out, leaving:

$\frac{v}{c} = \frac{1}{\sqrt{\varepsilon_r \mu_r}}$

Conclusion

The ratio of the speed of the electromagnetic wave in the medium ($v$) to its speed in vacuum ($c$) is determined by the square root of the product of the relative permeability and relative permittivity of the medium. The calculation shows this ratio to be $\frac{1}{\sqrt{\varepsilon_r \mu_r}}$.

Therefore, the correct option representing the ratio $\frac{v}{c}$ is $\frac{1}{\sqrt{\varepsilon_r \mu_r}}$.

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Important Questions from Electromagnetic Spectrum

  1. The correct order of electromagnetic spectrum with decreasing frequency is:

  2. The value of the proportionality constant μo/(4π) is equal to _________ Tm/A.

  3. Match List I with List II

    List – I

    List – II

    US New Military Bands for Microwaves

    Frequency range in GHz

    A.

    H band

    I.

    2.000 ‐ 3.000 GHz

    B.

    J band

    II.

    4.000 ‐ 6.000 GHz

    C.

    G band

    III.

    6.000 ‐ 8.000 GHz

    D.

    E band

    IV.

    10.000 ‐ 20.000 GHz

    Choose the correct answer from the options given below:

  4. The wave number of the limiting line of the series (visible) in hydrogen spectrum is:

  5. The wavelength in the bright-line emission spectrum of an element are

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