We need to determine the number of people who have an exam after B. To solve this, let's assign the days of the week to each person based on the given constraints. Here's the step-by-step reasoning:
Given these data points, let's try to position everyone:
The order now becomes:
| Monday | Tuesday | Wednesday | Thursday | Friday | Saturday | Sunday |
|---|---|---|---|---|---|---|
| T | U | R | B | L | O | E |
Now, let's count the number of people having exams after B on Thursday:
Thus, there are three people who have exams after B.
Therefore, the correct answer is: Three.
Each of P, Q, R, S, T, U and V has an exam on a different day of a week starting from Monday and ending on Sunday of the same week. V has an exam on Tuesday. Exactly 2 people have an exam between V and P. S has an exam immediately before T, and Q has an exam immediately after R. Only 1 person has an exam between T and R
How many people have an exam before S?
Each of P, Q, R, S, T, U and V has an exam on a different day of a week starting from Monday and ending on Sunday of the same week. Only five people have exams between T and Q. U has an exam on Thursday. S has an exam immediately after Q. R has an exam immediately after P. How many people have exams between V and T?
P, Q, R, S, T, U and V have an exam on different days of the week starting on Monday and ending on Sunday. Q has an exam on Wednesday. Exactly 4 people have an exam between T and U, neither of whom has an exam on Monday. R has an exam immediately before S and V has an exam immediately after S. P has an exam immediately before T.
How many people have an exam between P and R?