We need to determine the day E plays the game based on the given schedule constraints.
The game is played over 7 days, from Monday to Sunday.
We know C plays on Friday.
There is exactly one person between C and B. Since C is on Friday, B could be on Wednesday (Friday - 2 days) or Sunday (Friday + 2 days).
We are also told B does not play on Sunday.
Therefore, B must play on Wednesday.
Current Schedule:
A plays immediately before D, forming an 'AD' block. D does not play on Sunday.
Possible slots for the 'AD' block, considering B is on Wednesday and C is on Friday:
The only valid placement for 'AD' is Monday and Tuesday.
Current Schedule:
F plays immediately after G, forming a 'GF' block.
The remaining days are Thursday, Saturday, and Sunday.
The only consecutive available days for the 'GF' block are Saturday and Sunday.
Therefore, G plays on Saturday and F plays on Sunday.
Current Schedule:
The only person left is E, and the only day left is Thursday.
Final Schedule:
Thus, E plays the game on Thursday.
Each of J, K, L, M, N, O and P has an exam on a different day of a week starting from Monday and ending on Sunday of the same week. Only two people have exams before P. Only one person has an exam after L. Only three people have exams between P and J. Only one person has an exam between K and L. O has an exam immediately after M.
How many people have exams between M and N?