Data and address bus width of 8085 microprocessor respectively are
8 bits, 16 bits
The Intel 8085 is a significant microprocessor widely studied in computer architecture. Understanding its bus structure, specifically the data bus and the address bus, is fundamental. Buses act as communication channels connecting the CPU to memory and other peripherals.
The data bus is a set of electrical pathways used for transferring data between the microprocessor unit (MPU) and its connected devices, such as memory or I/O ports. It is bidirectional, meaning data can flow in both directions. The size, or width, of the data bus determines the amount of data that can be transferred in a single operation. For the 8085 microprocessor, the data bus has a width of $8 \text{ bits}$. This allows it to process and transfer 8 bits of data simultaneously.
The address bus is a set of pathways that carries the memory addresses or I/O addresses from the microprocessor to the memory or I/O devices. It is unidirectional, originating from the CPU. The width of the address bus dictates the total number of memory locations the microprocessor can access. The 8085 microprocessor utilizes a $16 \text{ bits}$ wide address bus. This enables it to address up to $2^{16}$ unique memory locations, totaling 65,536 memory locations (or 64 Kilobytes).
In summary, the specific bus widths for the 8085 microprocessor are:
This configuration makes the 8085 a capable 8-bit processor with a substantial memory addressing capability for its class.
The number of interrupts handled by 8051 microcontroller (other than Reset) is _____.
How many bits are used in the data bus of 8051 ?
16-bit registers consist of:
Arrange the following 8051 interrupts in increasing priority order.
A. Timer interrupt 0 (TF0)
B. Timer interrupt 1 (TF1)
C. External interrupt 0 (INT0)
D. External interrupt 1 (INT1)
Choose the correct answer from the options given below: