Monosaccharide Epimer P. D-mannose 1. C-3 epimer of D-glucose Q. D-allose 2. C-4 epimer of D-glucose R. D-galactose 3. C-4 epimer of D-mannose S. D-talose 4. C-2 epimer of D-glucose 5. C-5 epimer of D-glucose
To solve the problem of matching monosaccharides with their respective epimers, we need to understand what an epimer is. An epimer is a pair of stereoisomers that differ specifically at one carbon atom. Here is a step-by-step explanation of how to determine the correct match:
Given the above logic, the correct match is P-4; Q-1; R-2; S-3.
| Column I | Column II |
|---|---|
| P. Amylose | 1. $\beta$ ($1\to 4$) |
| Q. Sucrose | 2. $\alpha$ ($1\to 4$) |
| R. Amylopectin | 3. $\alpha 1\to \beta 2$ |
| S. Cellulose | 4. $\alpha$ ($1\to 4$), $\alpha$ ($1\to 6$) |
| Column I | Column II |
|---|---|
| P. Lectins | 1. Acts as ATP dependent pump to efflux out small molecules |
| Q. P-glycoprotein | 2. Targets lysosomal enzymes to their destination |
| R. Digitoxigenin | 3. Specific carbohydrate binding proteins |
| S. Mannose 6-phosphate | 4. Inhibits Na$^+$-K$^+$ pump |
An octapeptide composed of these L-amino acids – Lys, Thr, Ser, Met, Arg, Trp, Tyr, Glu was subjected to analyses with the following outcomes:
P. The N-terminal sequencing analysis by Sanger's method yielded 'Ser' at the N-terminus
Q. Chymotrypsin treatment gave a pentapeptide, a ‘Tyr' containing dipeptide and a free ‘Glu'
R. Cyanogen bromide treatment gave two tetrapeptides
S. Trypsin treatment gave two tripeptides and a dipeptide
Which one of the following is the correct octapeptide sequence?