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Question

Conversion of boron trifluoride to tetrafluoroborate accompanies

The correct answer is
increase in symmetry and bond elongation

Boron Trifluoride Conversion Analysis

The question asks about the changes accompanying the conversion of boron trifluoride ($BF_3$) to tetrafluoroborate. This typically refers to the formation of the $[BF_4]^-$ ion from the $BF_3$ molecule, often via reaction with a fluoride source ($F^-$).

  • Initial Molecule: Boron trifluoride ($BF_3$) has a trigonal planar geometry. The boron atom is $sp^2$ hybridized and has an incomplete octet. Its point group symmetry is $D_{3h}$.
  • Final Ion: Tetrafluoroborate ($[BF_4]^-$) has a tetrahedral geometry. The boron atom is $sp^3$ hybridized and has a complete octet. Its point group symmetry is $T_d$.

Symmetry Changes: $BF_3$ vs $[BF_4]^-$

The conversion involves a change in geometry from trigonal planar ($D_{3h}$) to tetrahedral ($T_d$). Both geometries exhibit high symmetry. However, the formation of the stable, octet-complete tetrahedral ion ($[BF_4]^-$) from the electron-deficient trigonal planar molecule ($BF_3$) is associated with an increase in symmetry in the context of achieving a more stable and complete electronic configuration and geometric arrangement.

Bond Length Changes Observed

The hybridization change affects the B-F bond length:

  • In $BF_3$, the $sp^2$ hybridized boron forms shorter B-F bonds (approximately 1.30 Å).
  • In $[BF_4]^-$, the $sp^3$ hybridized boron forms longer B-F bonds (approximately 1.35 Å).

This indicates a bond elongation occurs during the conversion.

Conclusion on Conversion Effects

Combining the observations:

  • Symmetry: Increases.
  • B-F Bond: Elongates.

Therefore, the conversion of boron trifluoride to tetrafluoroborate is accompanied by an increase in symmetry and bond elongation.

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Important Questions from Main Group Elements and Their Compounds

  1. __________ nitrides are termed by transition + inner transition metals.
  2. A non-metal ‘X’ occurs in nature in free state. It combines with hydrogen to form a gas, which is colourless and highly toxic. Apart from this, ‘X’ is oxidized to ‘$\text{XO}_2$’ which is a colourless, pungent and irritating gas. ‘X’ represents :
  3. For the following reaction sequence,


    X and Y, respectively, are

  4. The reaction of $PCl_3$ with $PhLi$ in 1:3 molar ratio yields X as one of the products, which on further treatment with $CH_3I$ gives Y. The reaction of Y with $n-BuLi$ gives product Z. The products X, Y and Z, respectively, are

  5. The correct statements regarding B among the following

    (i) Nuclear spin of 11B is greater than that of 10B

    (ii) The polarities of B - H bond and C-H bonds are opposite

    (iii) Cross - section of neutron absorption for 10B is much more than that of 11B

    (iv) B reacts with boiling aq. NaOH solution to form NaB(OH)4

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