The question asks about the changes accompanying the conversion of boron trifluoride ($BF_3$) to tetrafluoroborate. This typically refers to the formation of the $[BF_4]^-$ ion from the $BF_3$ molecule, often via reaction with a fluoride source ($F^-$).
The conversion involves a change in geometry from trigonal planar ($D_{3h}$) to tetrahedral ($T_d$). Both geometries exhibit high symmetry. However, the formation of the stable, octet-complete tetrahedral ion ($[BF_4]^-$) from the electron-deficient trigonal planar molecule ($BF_3$) is associated with an increase in symmetry in the context of achieving a more stable and complete electronic configuration and geometric arrangement.
The hybridization change affects the B-F bond length:
This indicates a bond elongation occurs during the conversion.
Combining the observations:
Therefore, the conversion of boron trifluoride to tetrafluoroborate is accompanied by an increase in symmetry and bond elongation.
For the following reaction sequence,

X and Y, respectively, are
The reaction of $PCl_3$ with $PhLi$ in 1:3 molar ratio yields X as one of the products, which on further treatment with $CH_3I$ gives Y. The reaction of Y with $n-BuLi$ gives product Z. The products X, Y and Z, respectively, are
The correct statements regarding B among the following
(i) Nuclear spin of 11B is greater than that of 10B
(ii) The polarities of B - H bond and C-H bonds are opposite
(iii) Cross - section of neutron absorption for 10B is much more than that of 11B
(iv) B reacts with boiling aq. NaOH solution to form NaB(OH)4