The question asks to identify a non-metal 'X' based on three key properties:
We need to evaluate the given options against these properties.
Non-metals like Sulphur ($\text{S}$), Carbon ($\text{C}$), and Phosphorus ($\text{P}$) are known to occur in nature in their elemental (free) state. Nitrogen ($\text{N}$) exists as a diatomic molecule ($\text{N}_2$) in the atmosphere, which is also considered a free state.
The reaction of 'X' with $\text{H}_2$ produces a colorless, highly toxic gas.
Based on this property, Sulphur and Phosphorus are strong candidates. Carbon and Nitrogen are less likely.
The element 'X' is oxidized to '$\text{XO}_2$', which is described as a colorless, pungent, and irritating gas.
Sulphur perfectly fits the description of forming the oxide '$\text{XO}_2$'.
By evaluating all the properties:
Therefore, the non-metal 'X' is Sulphur.
Final Answer: The final answer is Sulphur
For the following reaction sequence,

X and Y, respectively, are
The reaction of $PCl_3$ with $PhLi$ in 1:3 molar ratio yields X as one of the products, which on further treatment with $CH_3I$ gives Y. The reaction of Y with $n-BuLi$ gives product Z. The products X, Y and Z, respectively, are
The correct statements regarding B among the following
(i) Nuclear spin of 11B is greater than that of 10B
(ii) The polarities of B - H bond and C-H bonds are opposite
(iii) Cross - section of neutron absorption for 10B is much more than that of 11B
(iv) B reacts with boiling aq. NaOH solution to form NaB(OH)4