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Question

A non-metal ‘X’ occurs in nature in free state. It combines with hydrogen to form a gas, which is colourless and highly toxic. Apart from this, ‘X’ is oxidized to ‘$\text{XO}_2$’ which is a colourless, pungent and irritating gas. ‘X’ represents :

The correct answer is
Sulphur

Identify Non-Metal X Properties

The question asks to identify a non-metal 'X' based on three key properties:

  • It occurs in nature in the free state.
  • It reacts with hydrogen ($\text{H}_2$) to form a colorless, highly toxic gas.
  • It oxidizes to form '$\text{XO}_2$', a colorless, pungent, and irritating gas.

Analyzing Element Properties

We need to evaluate the given options against these properties.

1. Free State Occurrence

Non-metals like Sulphur ($\text{S}$), Carbon ($\text{C}$), and Phosphorus ($\text{P}$) are known to occur in nature in their elemental (free) state. Nitrogen ($\text{N}$) exists as a diatomic molecule ($\text{N}_2$) in the atmosphere, which is also considered a free state.

2. Reaction with Hydrogen

The reaction of 'X' with $\text{H}_2$ produces a colorless, highly toxic gas.

  • Sulphur reacts with $\text{H}_2$ to form Hydrogen Sulfide ($\text{H}_2\text{S}$). $\text{H}_2\text{S}$ is a colorless, highly toxic gas with a rotten egg smell.
  • Phosphorus reacts with $\text{H}_2$ to form Phosphine ($\text{PH}_3$). $\text{PH}_3$ is a colorless, highly toxic gas.
  • Carbon reacts with $\text{H}_2$ to form Methane ($\text{CH}_4$) and other hydrocarbons. $\text{CH}_4$ is colorless but not highly toxic.
  • Nitrogen reacts with $\text{H}_2$ under specific conditions to form Ammonia ($\text{NH}_3$). $\text{NH}_3$ is colorless and pungent but not considered highly toxic in the same category as $\text{H}_2\text{S}$ or $\text{PH}_3$.

Based on this property, Sulphur and Phosphorus are strong candidates. Carbon and Nitrogen are less likely.

3. Oxidation to XO2

The element 'X' is oxidized to '$\text{XO}_2$', which is described as a colorless, pungent, and irritating gas.

  • Sulphur oxidizes to form Sulfur Dioxide ($\text{SO}_2$). $\text{SO}_2$ is a colorless, pungent, and irritating gas. This matches the description of '$\text{XO}_2$'.
  • Phosphorus typically oxidizes to form oxides like Phosphorus Pentoxide ($\text{P}_4\text{O}_{10}$), which is a white solid, not a colorless gas of the type '$\text{XO}_2$'.
  • Carbon oxidizes to Carbon Dioxide ($\text{CO}_2$) or Carbon Monoxide ($\text{CO}$). $\text{CO}_2$ is colorless and odorless. $\text{CO}$ is toxic but not usually described as pungent/irritating in this context, and it is not of the formula type '$\text{XO}_2$'.
  • Nitrogen oxides include Nitrogen Dioxide ($\text{NO}_2$). $\text{NO}_2$ is reddish-brown, not colorless, although it is pungent and irritating.

Sulphur perfectly fits the description of forming the oxide '$\text{XO}_2$'.

Conclusion: Element X Identification

By evaluating all the properties:

  • Sulphur occurs in the free state.
  • Sulphur forms $\text{H}_2\text{S}$, a colorless, highly toxic gas.
  • Sulphur oxidizes to $\text{SO}_2$, a colorless, pungent, and irritating gas.

Therefore, the non-metal 'X' is Sulphur.

Final Answer: The final answer is Sulphur

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Important Questions from Main Group Elements and Their Compounds

  1. __________ nitrides are termed by transition + inner transition metals.
  2. For the following reaction sequence,


    X and Y, respectively, are

  3. The reaction of $PCl_3$ with $PhLi$ in 1:3 molar ratio yields X as one of the products, which on further treatment with $CH_3I$ gives Y. The reaction of Y with $n-BuLi$ gives product Z. The products X, Y and Z, respectively, are

  4. Conversion of boron trifluoride to tetrafluoroborate accompanies
  5. The correct statements regarding B among the following

    (i) Nuclear spin of 11B is greater than that of 10B

    (ii) The polarities of B - H bond and C-H bonds are opposite

    (iii) Cross - section of neutron absorption for 10B is much more than that of 11B

    (iv) B reacts with boiling aq. NaOH solution to form NaB(OH)4

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