Context free grammar is not closed under:
Complementation
Let's explore the closure properties of Context-Free Grammars (CFGs). A class of languages is said to be closed under an operation if applying that operation to languages within the class always produces a language that is also within that class. Context-Free Languages (CFLs), which are generated by CFGs, have certain closure properties.
We need to determine which of the given operations does not guarantee that the resulting language is still a Context-Free Language when applied to one or more CFLs.
If $L_1$ and $L_2$ are two Context-Free Languages, their union $L_1 \cup L_2$ is also a Context-Free Language. This property holds true. If $G_1$ generates $L_1$ and $G_2$ generates $L_2$, we can construct a new CFG $G$ that generates $L_1 \cup L_2$. The new grammar combines the rules of $G_1$ and $G_2$ under a new start symbol.
If $L_1$ and $L_2$ are two Context-Free Languages, their concatenation $L_1L_2$ is also a Context-Free Language. This property also holds. If $G_1$ generates $L_1$ and $G_2$ generates $L_2$, a new CFG can be constructed whose start symbol derives the start symbol of $G_1$ followed by the start symbol of $G_2$.
If $L$ is a Context-Free Language, its Kleene Star $L^*$ is also a Context-Free Language. This property holds. If $G$ generates $L$, a new CFG can be constructed to generate zero or more concatenations of strings from $L$.
If $L$ is a Context-Free Language, is its complement $\overline{L}$ (all strings over the alphabet $\Sigma$ that are *not* in $L$) also guaranteed to be a Context-Free Language? No, the class of Context-Free Languages is not closed under complementation.
Based on this analysis, Context Free Grammars (and the languages they generate) are not closed under Complementation.
| Operation | Is CFG/CFL Closed Under This Operation? |
|---|---|
| Union | Yes |
| Concatenation | Yes |
| Kleene Star | Yes |
| Complementation | No |
| Property | Closed (Yes/No) |
|---|---|
| Union | Yes |
| Concatenation | Yes |
| Kleene Star | Yes |
| Intersection | No |
| Complementation | No |
| Difference | No |
| Reverse | Yes |
| Homomorphism | Yes |
| Inverse Homomorphism | Yes |
Understanding closure properties is crucial in formal language theory and automata theory. Different classes of languages (like Regular Languages, Context-Free Languages, Context-Sensitive Languages, and Recursively Enumerable Languages) have different sets of closure properties. This helps classify and distinguish between the generative power of different grammar types or the recognition power of different automata types.
The fact that CFLs are not closed under complementation means that for every CFL $L$, its complement $\overline{L}$ is not necessarily context-free. There exist CFLs whose complements are not CFLs.
Consider the following statements about Context Free Language (CFL):
Statement I: CFL is closed under homomorphism.
Statement II: CFL is closed under complement.
Which of the following is correct?
Match List-I with List-II:
Where L1: Regular language
L2: Context-free language
L3: Recursive language
L4: Recursively enumerable language
List-1 | List-2 |
(a) L' 3 U L 4 | (i) Context-free language |
(b) L' 2 U L 3 | (ii) Recursively enumerable language |
(c) L 1* ∩ L 2 | (iii) Recursive language |
Choose the correct from those given below:
How can the decision algorithm be constructed for deciding whether context-free language L is finite?
(a) By Constructing redundant CFG in CNF generating language L
(b) By constructing non-redundant CFG G in CNF generating language L
(c) By constructing non-redundant CFG in CNF generating language L-{∧} (∧ stands for null)
Which of the following is correct?
Which of the following statements is true ?
Consider the following statements with respect to the language L = {a nb n|n≥ 0}
S 1: L 2is context free language
S 2: L kis context-free language for any given k ≥ 1
S 3: L̅ and L* are context free languages
Which one of the following is correct?