How can the decision algorithm be constructed for deciding whether context-free language L is finite? (a) By Constructing redundant CFG in CNF generating language L (b) By constructing non-redundant CFG G in CNF generating language L (c) By constructing non-redundant CFG in CNF generating language L-{∧} (∧ stands for null) Which of the following is correct?
(c) only
A language is considered finite if it contains a limited number of strings. For a context-free language (CFL), determining whether it is finite is a decidable problem. This means there is an algorithm that can tell us in a finite amount of time whether any given CFL is finite or infinite.
The core idea behind deciding if a CFL is finite involves examining the structure of its context-free grammar (CFG). Specifically, we need to check if the grammar can generate arbitrarily long strings, which would indicate an infinite language. This usually happens if there are derivation paths where a non-terminal can derive itself, directly or indirectly, and that non-terminal can also derive a string of terminals.
To make this check systematic, it's standard practice to first transform the CFG into a form that is easier to analyze. Chomsky Normal Form (CNF) is a suitable choice because all production rules are of the form \(A \to BC\) or \(A \to a\), where \(A, B, C\) are non-terminals and \(a\) is a terminal. This structure simplifies the analysis of derivation paths.
Let's analyze the options presented regarding constructing the decision algorithm for deciding whether a context-free language L is finite:
Therefore, the most common and reliable approach for constructing the decision algorithm for deciding whether a context-free language L is finite is to first handle the null string separately (if L contains it) and then check the finiteness of L - {&} using a non-redundant CFG in CNF. The standard algorithm for checking finiteness in a non-redundant CFG in CNF (without generating &) involves checking if any non-terminal variable is part of a dependency cycle in the derivation graph where the cycle corresponds to deriving a non-empty string. If such a cycle exists, the language L - {&} is infinite.
The procedure typically involves:
Option (c) directly addresses the standard method by considering a non-redundant CFG in CNF for the language L excluding the null string.
Based on the analysis of the standard decision algorithm for CFL finiteness, constructing a non-redundant CFG in CNF generating the language L-{&} is the appropriate step for deciding its finiteness. This form of the grammar simplifies the detection of infinite derivation paths.
| CFG Type | Language | Suitable for Finiteness Check? | Reason |
|---|---|---|---|
| Redundant CFG in CNF | L | No | Redundancy complicates cycle detection. |
| Non-redundant CFG in CNF | L | Less suitable | Handles most cases, but null string interaction with cycles might require careful separate handling or a modified algorithm. |
| Non-redundant CFG in CNF | L - {&} | Yes | Standard approach; simplifies cycle detection in the absence of null derivations. |
Therefore, option (c) describes the correct basis for constructing the decision algorithm.
| Term | Definition/Relevance |
|---|---|
| Context-Free Language (CFL) | A language generated by a Context-Free Grammar (CFG). |
| Finite Language | A language containing a finite number of strings. |
| Decidable Problem | A problem for which an algorithm exists that halts on all inputs and gives a correct yes/no answer. Deciding CFL finiteness is decidable. |
| Context-Free Grammar (CFG) | A formal grammar \(G = (V, \Sigma, R, S)\) used to generate strings in a CFL. |
| Chomsky Normal Form (CNF) | A standard form for CFGs where rules are \(A \to BC\) or \(A \to a\). Useful for algorithmic analysis. |
| Non-redundant CFG | A CFG where all non-terminals and terminals are "useful" (reachable from the start symbol and can derive a terminal string). Essential for reliable analysis. |
| Null String (& or \(\lambda\)) | The empty string. Its presence in the language L requires special handling when checking for finiteness using grammar structure. |
Deciding finiteness is one of several important decidable properties for Context-Free Languages. Other decidable properties include:
Properties that are *undecidable* for CFLs include:
Understanding decidability is fundamental in formal language theory and the study of computation. The algorithm for CFL finiteness relies on the structural properties of CFGs, particularly in CNF and when made non-redundant and free from null derivations (for the core infinite-generating mechanism check).
Consider the following statements about Context Free Language (CFL):
Statement I: CFL is closed under homomorphism.
Statement II: CFL is closed under complement.
Which of the following is correct?
Match List-I with List-II:
Where L1: Regular language
L2: Context-free language
L3: Recursive language
L4: Recursively enumerable language
List-1 | List-2 |
(a) L' 3 U L 4 | (i) Context-free language |
(b) L' 2 U L 3 | (ii) Recursively enumerable language |
(c) L 1* ∩ L 2 | (iii) Recursive language |
Choose the correct from those given below:
Which of the following statements is true ?
Consider the following statements with respect to the language L = {a nb n|n≥ 0}
S 1: L 2is context free language
S 2: L kis context-free language for any given k ≥ 1
S 3: L̅ and L* are context free languages
Which one of the following is correct?
Consider the following languages:
\({L_1} = \left\{ {{a^n}{b^n}{c^m}} \right\} \cup \left\{ {{a^n}{b^m}{c^m}} \right\},\;n,\;m \ge 0\)
\({L_2} = \{ w{w^R}|w \in \left\{ {a,\;b} \right\}*\}\) Where R represents reversible operation.
Which one of the following is (are) inherently ambiguous language(s)?