Considering extending the range of measuring instruments, the ratio \(\rm \frac{resistance \ of \ ammeter \ shunt }{resistance \ of \ voltmeter \ multiplier}=?\)
When extending the range of measuring instruments like ammeters and voltmeters, we use external resistances. For ammeters, a shunt resistance is connected in parallel, and for voltmeters, a multiplier resistance is connected in series.
The question asks for the ratio:
\(\rm \frac{resistance \ of \ ammeter \ shunt }{resistance \ of \ voltmeter \ multiplier}\)
Based on the roles of these components:
Therefore, the ratio of a very low value to a very large value will result in a very small overall value. For example, a milliohm value divided by a megohm value would yield a very small fraction.
Thus, the ratio \(\rm \frac{resistance \ of \ ammeter \ shunt }{resistance \ of \ voltmeter \ multiplier}\) is a very small value.
If an ammeter is to be used in place of a voltmeter, then we must connect with the ammeter :
An ammeter has a range of 0 - 10 A with an internal resistance of 0.1 Ω. In order to increase its range to 0 - 30 A, we need to add a resistance of
A moving coil meter has a resistance of 100 Ω and at 5 V it gives full scale deflection. Find the value of external resistance to be connected in series for measuring 300 V.
Which of the following is correct for ammeter?
An instrument with an internal resistance of 100 Ω and a full-scale current of 1 mA is to be converted into a DC voltmeter with range of 0 V - 500 V. Find the value of the resistance used as a multiplier.