Activity A Activity B Optimistic time ($t_o$) = 4 days Optimistic time ($t_o$) = 4 days Most likely time ($t_l$) = 7 days Most likely time ($t_l$) = 6 days Pessimistic time ($t_p$) = 16 days Pessimistic time ($t_p$) = 22 days
The standard deviation for project activities is calculated using the PERT (Program Evaluation and Review Technique) formula, which estimates the dispersion of activity durations.
The formula for standard deviation ($\sigma$) is:
$ \sigma = \frac{t_p - t_o}{6} $
Where:
Given values for Activity A:
Calculation:
$ \sigma_A = \frac{16 \text{ days} - 4 \text{ days}}{6} = \frac{12 \text{ days}}{6} = 2 \text{ days} $
Given values for Activity B:
Calculation:
$ \sigma_B = \frac{22 \text{ days} - 4 \text{ days}}{6} = \frac{18 \text{ days}}{6} = 3 \text{ days} $
The standard deviation for Activity A is 2 days, and the standard deviation for Activity B is 3 days.
If the data are skewed, which option of central tendency measure is the most unreliable indicator?
In a negatively skewed distribution
If the distribution is negatively skewed, then the:
The first four moments about the mean of distribution are 0, μ 2, 0.7 and 18.75. If the distribution is mesokurtic, the value of μ 2, is
If Mean > Median > Mode, the distribution is: