Activity A Activity B Optimistic time ($t_o$) = 4 days Optimistic time ($t_o$) = 4 days Most likely time ($t_l$) = 7 days Most likely time ($t_l$) = 6 days Pessimistic time ($t_p$) = 16 days Pessimistic time ($t_p$) = 22 days
The standard deviation for project activities is calculated using the PERT (Program Evaluation and Review Technique) formula, which estimates the dispersion of activity durations.
The formula for standard deviation ($\sigma$) is:
$ \sigma = \frac{t_p - t_o}{6} $
Where:
Given values for Activity A:
Calculation:
$ \sigma_A = \frac{16 \text{ days} - 4 \text{ days}}{6} = \frac{12 \text{ days}}{6} = 2 \text{ days} $
Given values for Activity B:
Calculation:
$ \sigma_B = \frac{22 \text{ days} - 4 \text{ days}}{6} = \frac{18 \text{ days}}{6} = 3 \text{ days} $
The standard deviation for Activity A is 2 days, and the standard deviation for Activity B is 3 days.
Suppose a 5-bit message is transmitted from a source to a destination through a noisy channel. The probability that a bit of the message gets flipped during transmission is 0.01. Flipping of each bit is independent of one another. The probability that the message is delivered error-free to the destination is ______ . (rounded off to three decimal places)
For a distribution with mean, median, mode and standard deviation 25, 24, 26 and 5 respectively, Karl Pearson's coefficient of skewness equals to:
Suppose two distributions have the same mean, same standard deviation and are equally skewed, but the first distribution is more peaked than the
other. This feature of the frequency distributions in which they are different are called: