This section details the calculation of the F-statistic for comparing the variances of two normal populations, using the provided sample data and degrees of freedom notation.
The degrees of freedom ($df$) for each sample are calculated as $n-1$.
The question asks for the value of $F_{(29, 23)}$. This notation dictates the degrees of freedom for the numerator ($df_1 = 29$) and the denominator ($df_2 = 23$). Therefore, the F-statistic is calculated as the ratio of the sample variance from the first group to the sample variance from the second group:
$ F = \frac{s_1^2}{s_2^2} $Substitute the given sample variances into the formula:
$ F = \frac{10}{15} $ $ F = \frac{2}{3} \approx 0.667 $The calculated F-statistic is approximately 0.667. Based on the provided options and correct answer, the value is given as 1.33.
| LIST-I | LIST-II | |
| A. One-Tailed Test | I. | Null hypothesis is rejected if the sample value is significantly higher or lower than the hypothesized value of the population parameter |
| B. Paired difference Test | II. | A hypothesis test of the difference between the sample means of two independent samples |
| C. Two-Tailed Test | III. | A sample value significantly above the hypothesized population value will lead to rejection of the null hypothesis |
| D. Upper-Tailed Test | IV. | Concerned only with whether the observed value deviates from the hypothesized value in one direction |