$$a. H_2O_2 + b. KMnO_4 + c. H_2SO_4 \to d. K_2SO_4 + e. MnSO_4 + f. H_2O + g. O_2$$
Select the correct answer from the codes given below :
The goal is to find the stoichiometric coefficients ($a, b, c, d, e, f, g$) that correctly balance the given chemical equation:
$a. H_2O_2 + b. KMnO_4 + c. H_2SO_4 \to d. K_2SO_4 + e. MnSO_4 + f. H_2O + g. O_2$This is a redox reaction where $H_2O_2$ is oxidized and $KMnO_4$ is reduced in an acidic medium ($H_2SO_4$). We will check the atom balance using the coefficients from the correct option.
Let's test the coefficients provided in Option B: $a=1, b=2, c=3, d=1, e=2, f=4, g=3$.
Substituting these values into the equation gives:
$1 H_2O_2 + 2 KMnO_4 + 3 H_2SO_4 \to 1 K_2SO_4 + 2 MnSO_4 + 4 H_2O + 3 O_2$We verify the number of atoms for each element on both the reactant (left) and product (right) sides.
| Element | Reactant Side | Product Side | Balanced? |
|---|---|---|---|
| K | $2 \times 1 = 2$ | $1 \times 2 = 2$ | Yes |
| Mn | $2 \times 1 = 2$ | $2 \times 1 = 2$ | Yes |
| S | $3 \times 1 = 3$ | $(1 \times 1) + (2 \times 1) = 1 + 2 = 3$ | Yes |
| H | $(1 \times 2) + (3 \times 2) = 2 + 6 = 8$ | $4 \times 2 = 8$ | Yes |
| O | $(1 \times 2) + (2 \times 4) + (3 \times 4) = 2 + 8 + 12 = 22$ | $(1 \times 4) + (2 \times 4) + (4 \times 1) + (3 \times 2) = 4 + 8 + 4 + 6 = 22$ | Yes |
All elements are balanced with the coefficients $a=1, b=2, c=3, d=1, e=2, f=4, g=3$.
| LIST-I | LIST-II | |
| A. One-Tailed Test | I. | Null hypothesis is rejected if the sample value is significantly higher or lower than the hypothesized value of the population parameter |
| B. Paired difference Test | II. | A hypothesis test of the difference between the sample means of two independent samples |
| C. Two-Tailed Test | III. | A sample value significantly above the hypothesized population value will lead to rejection of the null hypothesis |
| D. Upper-Tailed Test | IV. | Concerned only with whether the observed value deviates from the hypothesized value in one direction |