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Question

Consider the problem of drawing a sample of size 2 from a finite population of size 20. The sampling is done with replacement using probability proportional to size sampling scheme. The normed size measures $p_1, \cdots, p_{20}$ are given by $p_i = \frac{1}{40}$, $i = 1, \cdots, 10, \; p_i = \frac{3}{40}$, $i = 11, \cdots, 20$. The expected number of distinct units drawn is

The correct answer is
$\frac{31}{16}$

Expected Distinct Units Calculation

The problem asks for the expected number of distinct units drawn when sampling 2 units from a population of 20 with replacement, using probability proportional to size (PPS) sampling. The probabilities $p_i$ are given.

Formula for Expected Distinct Units

For sampling with replacement, the expected number of distinct units ($E(V)$) in a sample of size $n$ from a population of size $N$ is given by:

$E(V) = N - \sum_{i=1}^{N} (1 - p_i)^n$

Here, $N = 20$ and the sample size $n = 2$.

Given Probabilities

  • For units $i = 1, \cdots, 10$ (10 units): $p_i = \frac{1}{40}$.
  • For units $i = 11, \cdots, 20$ (10 units): $p_i = \frac{3}{40}$.

Let's verify the sum of probabilities: $10 \times \frac{1}{40} + 10 \times \frac{3}{40} = \frac{10}{40} + \frac{30}{40} = \frac{40}{40} = 1$. The probabilities are correctly normed.

Calculation Steps

We need to calculate the term $\sum_{i=1}^{N} (1 - p_i)^n$. Since $n=2$, we calculate $(1 - p_i)^2$.

  1. Calculate $(1 - p_i)^2$ for the first group of 10 units:
    For $p_i = \frac{1}{40}$, $(1 - p_i)^2 = \left(1 - \frac{1}{40}\right)^2 = \left(\frac{39}{40}\right)^2 = \frac{1521}{1600}$.
  2. Calculate $(1 - p_i)^2$ for the second group of 10 units:
    For $p_i = \frac{3}{40}$, $(1 - p_i)^2 = \left(1 - \frac{3}{40}\right)^2 = \left(\frac{37}{40}\right)^2 = \frac{1369}{1600}$.
  3. Calculate the sum $\sum_{i=1}^{20} (1 - p_i)^2$:
    The sum consists of 10 terms of the first type and 10 terms of the second type.
    $ \sum_{i=1}^{20} (1 - p_i)^2 = 10 \times \left(\frac{39}{40}\right)^2 + 10 \times \left(\frac{37}{40}\right)^2 $ $ = 10 \times \frac{1521}{1600} + 10 \times \frac{1369}{1600} $ $ = \frac{15210}{1600} + \frac{13690}{1600} = \frac{28900}{1600} = \frac{289}{16} $
  4. Calculate the Expected Number of Distinct Units $E(V)$:
    $ E(V) = N - \sum_{i=1}^{20} (1 - p_i)^2 $ $ E(V) = 20 - \frac{289}{16} $ $ E(V) = \frac{20 \times 16}{16} - \frac{289}{16} = \frac{320}{16} - \frac{289}{16} = \frac{320 - 289}{16} $ $ E(V) = \frac{31}{16} $

Final Answer

The expected number of distinct units drawn is $\frac{31}{16}$.

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Important Questions from Ratio And Regression

  1. Consider a finite population of size $N$. Let $T_1$ be the sample mean based on a sample of size $n$ under simple random sampling with replacement (SRSWR) scheme. Let $T_2$ be the sample mean based on a stratified random sample of size $n$ where the samples are drawn from each of 4 strata using SRSWR scheme under proportional allocation. Then which of the following are sufficient conditions for $\text{Var}(T_1) = \text{Var}(T_2)$ to hold?
  2. Suppose there are $k$ strata of $N = kM$ units each with size $M$. Draw a sample of size $n_i$ with replacement from the $i^{\text{th}}$ stratum and denote by $\bar{y}_i$ the sample mean of the study variable selected in the $i^{\text{th}}$ stratum, $i = 1, 2, \dots, k$. Define
    $$ \bar{y}_s = \frac{1}{k}\sum_{i=1}^k \bar{y}_i \text{ and } \bar{y}_w = \frac{\sum_{i=1}^k n_i \bar{y}_i}{n} $$
    Which of the following is necessarily true?

  3. Suppose we draw a random sample of size $n$ from a population of size $N$, where $1 < n < N$, using simple random sampling without replacement scheme. Let $P$ be the population proportion of units possessing a particular attribute and $p$ be the corresponding sample proportion. Which of the following is an unbiased estimator for $P(1 - P)$?
  4. Suppose there are $k$ groups each consisting of $N$ boys. We want to estimate the mean age $\mu$ of these $kN$ boys. Fix $1 < n < N$ and consider the following two sampling schemes. 

    I. Draw a simple random sample without replacement of size $kn$ out of all $kN$ boys. 

    II. From each of the $k$ groups draw a simple random sample with replacement of size $n$. 

    Let $\bar{Y}$ and $\bar{Y}_G$ be the respective sample mean ages for the two schemes. Which of the following are true?

  5. A sample of size $n (\ge 2)$ is drawn without replacement from a finite population of size $N$, using an arbitrary sampling scheme. Let $\pi_i$ denote the inclusion probability of the $i$-th unit and $\pi_{ij}$, the joint inclusion probability of units $i$ and $j, 1 \le i < j \le N$. Which of the following statements is always true?
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