Consider the following terminology and match List 1 and List 2 and choose the correct answer from the code given below b = branch factor d = depth of shallowest solution M = Maximum depth of the search tree I = depth limit List 1 List 2 a) BFS i) O(bd) b) DFS ii) O(b d) c) Depth – Limited Search iii) O(bm) d) Iterative deepening Search iv) O(bl)
a-ii, b-iii, c-iv, d-i
This question asks us to match different search algorithms used in Artificial Intelligence and computer science with their time complexities. We are given specific variables:
Let's analyze each search algorithm and its typical time complexity in the worst case for finding a solution.
BFS explores the search space level by level. To find a solution at depth 'd', it needs to visit all nodes up to depth d-1 and potentially some nodes at depth d. The number of nodes at depth k in a tree with branch factor b is \(b^k\). The total number of nodes up to depth d is \(1 + b + b^2 + \dots + b^d\). This sum is \(O(b^d)\). Therefore, the time complexity of BFS is typically given as \(O(b^d)\).
Matching: BFS (a) corresponds to \(O(b^d)\) (ii).
Standard DFS explores as deeply as possible along each branch before backtracking. In the worst case, if the goal is at the end of the last explored branch or deeper than where the algorithm stops, it might explore the entire tree up to the maximum depth M. The number of nodes in a tree up to depth M is \(1 + b + b^2 + \dots + b^M\), which is \(O(b^M)\). Therefore, the time complexity of DFS can be \(O(b^M)\).
Matching: DFS (b) corresponds to \(O(b^M)\) (iii).
Depth-Limited Search is a variation of DFS that imposes a predefined depth limit 'l'. It behaves like DFS but stops exploring any path once it reaches depth 'l'. The time complexity is determined by the number of nodes within the depth limit 'l'. The number of nodes up to depth l is \(1 + b + b^2 + \dots + b^l\), which is \(O(b^l)\).
Matching: Depth – Limited Search (c) corresponds to \(O(b^l)\) (iv).
Iterative Deepening Search performs a series of Depth-Limited Searches with increasing limits (0, 1, 2, ..., d). Although nodes at shallower depths are visited multiple times, the total number of nodes visited is dominated by the nodes visited in the final iteration (at depth d). The total complexity is the sum of nodes visited in each DLS: \(O(b^0) + O(b^1) + \dots + O(b^d)\). This sum is approximately \(O(b^d)\). Specifically, it's \(O(b^d)\) because the number of nodes at the deepest level 'd' is much larger than the sum of nodes at all shallower levels. For example, \(1+b+b^2+...+b^d \lt b^{d+1}\). A tighter analysis shows it's \(O(b^d)\).
Matching: Iterative deepening Search (d) corresponds to \(O(b^d)\) (i).
| List 1 (Algorithm) | List 2 (Time Complexity) | Matching |
|---|---|---|
| a) BFS | ii) \(O(b^d)\) | a-ii |
| b) DFS | iii) \(O(b^M)\) | b-iii |
| c) Depth – Limited Search | iv) \(O(b^l)\) | c-iv |
| d) Iterative deepening Search | i) \(O(b^d)\) | d-i |
The correct matching is a-ii, b-iii, c-iv, d-i.
| Algorithm | Time Complexity | Space Complexity | Optimal? (if edge costs = 1) | Complete? |
|---|---|---|---|---|
| BFS | \(O(b^d)\) | \(O(b^d)\) | Yes | Yes |
| DFS | \(O(b^M)\) | \(O(bM)\) | No | No (if infinite paths exist) |
| Depth-Limited Search | \(O(b^l)\) | \(O(bl)\) | No | No (if shallowest solution is > l) |
| Iterative Deepening Search | \(O(b^d)\) | \(O(bd)\) | Yes | Yes |
Big O notation (\(O\)) is used to describe the upper bound of an algorithm's time or space complexity. It tells us how the performance scales with the size of the input in the worst case. In the context of search algorithms on trees or graphs, the "input size" relates to the size of the search space explored.
Understanding these complexities helps in choosing the appropriate search algorithm based on the characteristics of the problem, such as the size of the search space, the expected depth of the solution, and available memory.
Consider following sentences regarding A*, an informed search strategy in Artificial
Intelligence (AI).
(a) A* expands all nodes with f(n) < C*.
(b) A* expands no nodes with f(n) /C*.
(c) Pruning is integral to A*.
Here, C* is the cost of the optimal solution path.
Which of the following is correct with respect to the above statements ?
The process of removing details from a given state representation is called ______
In heuristic search algorithms in Artificial Intelligence (AI), if a collection of admissible heuristics h 1.......h mis available for a problem and none of them dominates any of the others, which should we choose ?
Consider the following statements related to AND-OR Search algorithm.
S1: A solution is a subtree that has a goal node at every leaf.
S2: OR nodes are analogous to the branching in a deterministic environment
S3: AND nodes are analogous to the branching in a non-deterministic environment.
Which one of the following is true referencing the above statements?
Choose the correct answer from the code given below:
Consider the following statements
S1: A heuristic is admissible if it never overestimates the cost to reach the goal
S2: A heuristic is monotonous if it follows triangle inequality property.
Which one of the following is true referencing the above statements?