Consider following sentences regarding A*, an informed search strategy in Artificial Intelligence (AI). (a) A* expands all nodes with f(n) < C*. (b) A* expands no nodes with f(n) /C*. (c) Pruning is integral to A*. Here, C* is the cost of the optimal solution path. Which of the following is correct with respect to the above statements ?
Both statement (a) and statement (b) are true.
Let's analyze the provided statements regarding A*, an informed search strategy in Artificial Intelligence. A* uses an evaluation function, $f(n) = g(n) + h(n)$, where $g(n)$ is the cost from the start node to node $n$, and $h(n)$ is the estimated cost from node $n$ to the goal. For A* to be optimal, the heuristic function $h(n)$ must be admissible, meaning it never overestimates the true cost to the goal. $C^*$ represents the cost of the optimal solution path.
Statement (a) claims that A* expands all nodes $n$ for which $f(n) < C^*$. In A* search, nodes are selected for expansion based on their $f(n)$ value, always choosing the node with the lowest value from the open list. If the heuristic $h(n)$ is admissible, $f(n) = g(n) + h(n) \le g(n) + h^*(n)$, where $h^*(n)$ is the true minimum cost from node $n$ to the goal. The true cost of any path through node $n$ to the goal is at least $g(n) + h^*(n)$. The optimal path cost is $C^*$. If a node $n$ has $f(n) < C^*$, it means its estimated total cost is less than the known optimal path cost $C^*$. A* needs to explore such nodes because they could potentially lead to a path with a cost less than or equal to $C^*$. Since A* explores nodes in increasing order of $f(n)$, any node with $f(n) < C^*$ must be expanded before the search can confirm that a path with cost $C^*$ is optimal and stop. Thus, statement (a) is true for A* with an admissible heuristic.
Statement (b) asserts that A* expands no nodes $n$ where $f(n) > C^*$. A* terminates when it selects the goal node for expansion. With an admissible heuristic, the first time the goal node is selected, its $f(goal)$ value will be equal to $g(goal) + h(goal)$. Assuming $h(goal)=0$ (a standard property of admissible heuristics), $f(goal) = g(goal) = C^*$ for the optimal path. Since A* always selects the node with the lowest $f(n)$ from the open list, any node selected before the goal node must have $f(n) \le f(goal) = C^*$. Therefore, A* will not select any node $n$ for expansion if $f(n) > C^*$ because the goal node (or potentially another node on an optimal path) with $f$-value $C^*$ would have been selected first. Thus, statement (b) is true for A* with an admissible heuristic.
Statement (c) suggests that pruning is integral to A*. While A* is an informed search algorithm that uses a heuristic to guide its search and is much more efficient than uninformed methods like Breadth-First Search or Uniform Cost Search, the term 'pruning' isn't typically used as a core description of its mechanism. Pruning usually refers to actively eliminating branches of the search space that are proven not to contain an optimal solution (e.g., alpha-beta pruning in game trees). A* focuses its exploration on nodes with lower $f$-values, effectively avoiding exploring paths with high estimated costs. This guided exploration is different from explicitly 'pruning' subtrees based on strict bounds or rules. Therefore, while A* is efficient and avoids exploring many nodes, calling 'pruning' integral might be inaccurate or non-standard terminology. Statement (c) is likely false or misleading in this context.
Based on the analysis, statement (a) and statement (b) are true for A* search with an admissible heuristic, while statement (c) is not typically considered true in the standard definition and operation of A*.
Therefore, the correct option is that both statement (a) and statement (b) are true.
| Statement | Truth Value (with Admissible Heuristic) | Explanation |
|---|---|---|
| (a) A* expands all nodes with $f(n) < C^*$. | True | A* expands nodes in increasing order of $f(n)$. Any node with $f(n) < C^*$ must be explored to ensure optimality. |
| (b) A* expands no nodes with $f(n) > C^*$. | True | When A* selects the goal (with $f(goal) = C^*$), it stops. Any node remaining on the open list has $f(n) \ge C^*$. Nodes selected before the goal have $f(n) \le C^*$. |
| (c) Pruning is integral to A*. | False/Debatable | A* uses a heuristic for guided exploration, which is different from explicit pruning techniques. |
| Concept | Description |
|---|---|
| A* Search | An informed search algorithm that combines Uniform Cost Search and Greedy Best-First Search using $f(n) = g(n) + h(n)$. |
| $g(n)$ | Cost from the start node to current node $n$. |
| $h(n)$ | Estimated cost from current node $n$ to the goal node (heuristic). |
| $f(n)$ | Evaluation function: $f(n) = g(n) + h(n)$. Estimated total cost of the path through node $n$ to the goal. |
| Admissible Heuristic | A heuristic $h(n)$ is admissible if $h(n) \le h^*(n)$ for all nodes $n$, where $h^*(n)$ is the true minimum cost from $n$ to the goal. Admissibility guarantees optimality for A*. |
| Consistent Heuristic | A heuristic $h(n)$ is consistent if for every node $n$ and every neighbor $n'$ of $n$, $h(n) \le cost(n, n') + h(n')$. Consistency implies admissibility. |
| $C^*$ | The cost of the optimal solution path from the start node to the goal node. |
| Optimality of A* | A* finds an optimal path to the goal if the heuristic $h(n)$ is admissible. |
A* search is a widely used algorithm in Artificial Intelligence for pathfinding and graph traversal. Its efficiency and optimality depend heavily on the quality of the heuristic function used. A good heuristic can significantly reduce the number of nodes expanded compared to uninformed search methods.
Understanding the properties related to $f(n)$ and $C^*$ is crucial for comprehending why A* guarantees finding an optimal path. By always expanding the node with the lowest $f(n)$, A* explores the most promising paths first, ensuring that an optimal path is found before any path that is guaranteed to be suboptimal (i.e., those with $f(n) > C^*$). The nodes with $f(n) < C^*$ must be expanded as they represent paths with an estimated cost lower than the optimal, and their true cost needs to be evaluated to ensure they don't lead to a better solution.
The process of removing details from a given state representation is called ______
In heuristic search algorithms in Artificial Intelligence (AI), if a collection of admissible heuristics h 1.......h mis available for a problem and none of them dominates any of the others, which should we choose ?
Consider the following terminology and match List 1 and List 2 and choose the correct answer from the code given below
b = branch factor
d = depth of shallowest solution
M = Maximum depth of the search tree
I = depth limit
List 1 | List 2 |
a) BFS | i) O(bd) |
b) DFS | ii) O(b d) |
c) Depth – Limited Search | iii) O(bm) |
d) Iterative deepening Search | iv) O(bl) |
Consider the following statements related to AND-OR Search algorithm.
S1: A solution is a subtree that has a goal node at every leaf.
S2: OR nodes are analogous to the branching in a deterministic environment
S3: AND nodes are analogous to the branching in a non-deterministic environment.
Which one of the following is true referencing the above statements?
Choose the correct answer from the code given below:
Consider the following statements
S1: A heuristic is admissible if it never overestimates the cost to reach the goal
S2: A heuristic is monotonous if it follows triangle inequality property.
Which one of the following is true referencing the above statements?