Consider the following statements in respect of square matrices A, B, C each of same order n : 1. AB = AC ⇒ B = C if A is non-singular 2. If BX = CX for every column matrix X having n rows then B = C Which of the statements given above is/are correct ?
Both 1 and 2
Let's analyze each statement about square matrices A, B, and C of the same order n.
This statement explores the property of cancellation in matrix multiplication when one of the matrices is non-singular. A square matrix A is non-singular if and only if its inverse, denoted as \(A^{-1}\), exists. When \(A^{-1}\) exists, we can use it to manipulate matrix equations.
Given the equation: \(AB = AC\)
Since A is non-singular, we can multiply both sides of the equation by \(A^{-1}\) from the left:
\(A^{-1}(AB) = A^{-1}(AC)\)
Using the associative property of matrix multiplication \((XY)Z = X(YZ)\), we can group the terms:
\((A^{-1}A)B = (A^{-1}A)C\)
We know that the product of a matrix and its inverse is the identity matrix, denoted by I (\(A^{-1}A = I\)). The identity matrix behaves like the number 1 in multiplication; multiplying any matrix by the identity matrix (of compatible size) results in the original matrix (\(IB = B\) and \(IC = C\)).
Substituting \(A^{-1}A = I\) into the equation:
\(IB = IC\)
Which simplifies to:
\(B = C\)
Thus, if A is a non-singular matrix and \(AB = AC\), it necessarily follows that \(B = C\). Statement 1 is correct.
This statement checks the implication of a matrix equation holding true for all possible column vectors. We are given that \(BX = CX\) for every column matrix X of size n x 1. Matrices B and C are square matrices of order n.
We can rearrange the equation \(BX = CX\) as follows:
\(BX - CX = 0\)
Using the distributive property of matrix multiplication \((B - C)X = BX - CX\), we can factor out the matrix X:
\((B - C)X = 0\)
Here, 0 represents the zero column matrix of size n x 1.
This equation \((B - C)X = 0\) must hold for *every* possible column matrix X of size n x 1.
Consider the standard basis vectors for X. These are column matrices where one element is 1 and all other elements are 0. For example, the first standard basis vector \(e_1\) is a column matrix with 1 in the first row and 0s elsewhere, \(e_2\) has 1 in the second row and 0s elsewhere, and so on, up to \(e_n\).
A matrix where every column is the zero vector is the zero matrix. Therefore, \((B - C)\) must be the zero matrix.
\(B - C = 0\)
Adding C to both sides gives:
\(B = C\)
Thus, if \(BX = CX\) for every column matrix X, then \(B = C\). Statement 2 is correct.
Both Statement 1 and Statement 2 are correct properties concerning square matrices. Statement 1 demonstrates cancellation with a non-singular matrix, and Statement 2 shows that if two matrices produce the same result when multiplied by any vector, the matrices must be equal.
Based on the analysis, both statements are correct.
If \(A=\left[\begin{array}{l}1 \\ 2 \\ 3\end{array}\right]\), then what is the value of det(I + AA'), where I is the 3 × 3 identity matrix?
If \(A=\left[\begin{array}{lll} 2 & 0 & 0 \\ 0 & 3 & 0 \\ 0 & 0 & 4 \end{array}\right]\), then which of the following statements are correct?
1. An will always be singular for any positive integer n.
2. An will always be a diagonal matrix for any positive integer n.
3. An will always be a symmetric matrix for any positive integer n.
Select the correct answer using the code given below:
If \(A=\left[\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{array}\right]\), then what is 23A3 - 19A2 - 4A equal to ?
If A is an orthogonal matrix of order 3 and \({\rm{B}} = \left[ {\begin{array}{*{20}{c}} 1&2&3\\ { - 3}&0&2\\ 2&5&0 \end{array}} \right]\) , then which of the following is/are correct?
1. |AB| = ± 47
2. AB = BA
Select the correct answer using the code given below:If \({\rm{E}}\left( {\rm{\theta }} \right) = \left[ {\begin{array}{*{20}{c}} {\cos {\rm{\theta }}}&{\sin {\rm{\theta }}}\\ { - \sin {\rm{\theta \;}}}&{\cos {\rm{\theta }}} \end{array}} \right]\) then E(α) E(β) is equal to