Consider the following inequalities.
(i) $2x - 1 > 7$
(ii) $2x - 9 < 1$
Which one of the following expressions below satisfies the above two inequalities?
We need to solve the first inequality:
$2x - 1 > 7$
So, the solution for the first inequality is $x > 4$.
Next, we solve the second inequality:
$2x - 9 < 1$
The solution for the second inequality is $x < 5$.
We need a value of $x$ that satisfies *both* inequalities simultaneously. This means $x$ must be greater than 4 AND less than 5.
Combining $x > 4$ and $x < 5$ gives the combined inequality:
$4 < x < 5$
Now, compare this result with the given options:
The expression $4 < x < 5$ exactly matches Option 3.
Consider the following inequalities.
(i) $3p - q < 4$
(ii) $3q - p < 12$
Which one of the following expressions below satisfies the above two inequalities?
Which one of the following is a representation (not to scale and in bold) of all values of $x$ satisfying the inequality $2 – 5x \le \frac{6x-5}{3}$on the real numberline?
Consider the following inequalities
$p^2 - 4q < 4$
$3p + 2q < 6$
where $p$ and $q$ are positive integers.
The value of $(p + q)$ is __________