To find the wavelength ($\lambda_{max}$) at which maximum power is radiated by a blackbody, we use Wien's Displacement Law. The law states:
$ \lambda_{max} T = b $Where:
The given temperature is $15^\circ\text{C}$. We need to convert this to Kelvin:
$ T(\text{K}) = T(^\circ\text{C}) + 273.15 $ $ T = 15 + 273.15 = 288.15 \text{ K} $Now, substitute the values into Wien's formula to find $\lambda_{max}$:
$ \lambda_{max} = \frac{b}{T} $ $ \lambda_{max} = \frac{2.898 \times 10^{-3} \text{ m}\cdot\text{K}}{288.15 \text{ K}} $ $ \lambda_{max} \approx 1.0057 \times 10^{-5} \text{ m} $The options are given in micrometers ($\mu\text{m}$). Convert the calculated wavelength:
Since $1 \text{ m} = 10^6 \mu\text{m}$:
$ \lambda_{max} \approx (1.0057 \times 10^{-5} \text{ m}) \times (10^6 \mu\text{m}/\text{m}) $ $ \lambda_{max} \approx 10.057 \mu\text{m} $The calculated wavelength is approximately $10.1 \mu\text{m}$. This corresponds to the wavelength at which the Earth, considered as a blackbody at $15^\circ\text{C}$, radiates maximum power.
| List - I (Decomposition Processes) | List - II (Function) |
|---|---|
| A. Leaching | I. Degradation of humus by microbes to release inorganic nutrients |
| B. Catabolism | II. Accumulation of a colloidal dark coloured amorphous substance, which is a reservoir of nutrients |
| C. Humification | III. Bacterial and Fungal enzymes degrade detritus into simpler inorganic substances |
| D. Mineralization | IV. Water soluble inorganic nutrients go down into the soil and get precipitated |