Consider a discrete-time sequencebr
$x[n] = \begin{cases} (0.2)^n, & 0 \le n \le 7 \\ 0, & \text{otherwise} \end{cases}$
The region of convergence of $X(z)$, the z-transform of $x[n]$, consists of
The z-transform of a discrete-time sequence $x[n]$ is defined as:
Given the sequence:
The z-transform $X(z)$ is:
This can be rewritten as:
This represents a finite geometric series. The region of convergence (ROC) is the set of z values for which the z-transform sum converges.
The terms in the summation are $(0.2)^n z^{-n}$. For these terms to be defined, $z^{-n}$ must be defined. The term $z^{-n}$ is undefined when $z=0$ for any $n > 0$. Since the sum includes terms for $n=1$ through $n=7$, the value $z=0$ must be excluded from the ROC.
The sum can be explicitly written as:
This finite sum converges for all values of $z$ except $z=0$. The term $z=\infty$ does not cause divergence because $z^{-n} \to 0$ for $n>0$ as $z \to \infty$. The specific value $z=0.2$ results in a finite sum: $\sum_{n=0}^{7} (0.2)^n (0.2)^{-n} = \sum_{n=0}^{7} 1 = 8$. Thus, $z=0.2$ is included in the ROC.
The ROC is determined by the values of $z$ for which the sum $X(z)$ exists. Based on the analysis of the $z^{-n}$ terms, the ROC excludes $z=0$. Therefore, the ROC consists of all values of $z$ except $z = 0$.
The z transform of e −t sampled at 10 Hz will be:
What is the set of all values of z for which X(z) attains a finite value?
The z transform of the following real exponential sequence
x(n) = {a n ;n >= 0} , {= 0 ; n < 0} and a > 0 is given by
What will be the z-transform of a Unit step function ?
The z-transform of a causal periodic signal can be determined from the knowledge of the z-transform of its: