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Question

Consider a Boolean function $F$ with the following minterm expression:
$$F(P, Q, R, S) = \sum m(1, 2, 3, 4, 5, 7, 10, 12, 13, 14)$$
Which of the following options is/are the minimal sum-of-products expression(s) of $F$?

Minimal Sum-of-Products Expression for Boolean Function F

The problem asks for the minimal sum-of-products (SOP) expression for the Boolean function $F$ defined by the minterms $F(P, Q, R, S) = \sum m(1, 2, 3, 4, 5, 7, 10, 12, 13, 14)$. We need to verify which of the given options represent a minimal SOP form.

Step 1: Karnaugh Map (K-map) Representation

We represent the function $F$ using a 4-variable Karnaugh map. The map is filled with '1's at the specified minterm locations.

Minterms to include: 1, 2, 3, 4, 5, 7, 10, 12, 13, 14.

K-map structure (PQ rows, RS columns):

Karnaugh Map for F
PQ RS
00 01 11 10
00 0 1 1 1
01 1 1 1 0
11 1 1 0 1
10 0 0 0 1

Step 2: Analyze Option B

Option B is given by: $\bar{P}S + Q\bar{R} + \bar{P}\bar{Q}R + P R \bar{S}$. Let's check the minterms covered by each term:

  • $\bar{P}S$: Covers minterms where P=0 and S=1. Locations: (0001, 0011, 0101, 0111) -> {1, 3, 5, 7}.
  • $Q\bar{R}$: Covers minterms where Q=1 and R=0. Locations: (0100, 0101, 1100, 1101) -> {4, 5, 12, 13}.
  • $\bar{P}\bar{Q}R$: Covers minterms where P=0, Q=0, R=1. Locations: (0010, 0011) -> {2, 3}.
  • $P R \bar{S}$: Covers minterms where P=1, R=1, S=0. Locations: (1010, 1110) -> {10, 14}.

Combining the minterms covered by Option B: {1, 3, 5, 7} $\cup$ {4, 5, 12, 13} $\cup$ {2, 3} $\cup$ {10, 14} = {1, 2, 3, 4, 5, 7, 10, 12, 13, 14}.

This covers all the required minterms for function $F$. Option B provides a 4-term SOP.

Step 3: Analyze Option D

Option D is given by: $\bar{P}S + Q\bar{R} + P Q \bar{S} + \bar{Q}R\bar{S}$. Let's check the minterms covered:

  • $\bar{P}S$: Covers {1, 3, 5, 7}.
  • $Q\bar{R}$: Covers {4, 5, 12, 13}.
  • $P Q \bar{S}$: Covers minterms where P=1, Q=1, S=0. Locations: (1100, 1110) -> {12, 14}.
  • $\bar{Q}R\bar{S}$: Covers minterms where Q=0, R=1, S=0. Locations: (0010, 1010) -> {2, 10}.

Combining the minterms covered by Option D: {1, 3, 5, 7} $\cup$ {4, 5, 12, 13} $\cup$ {12, 14} $\cup$ {2, 10} = {1, 2, 3, 4, 5, 7, 10, 12, 13, 14}.

This also covers all the required minterms for function $F$. Option D provides a 4-term SOP.

Step 4: Conclusion on Minimality

Both options B and D provide valid SOP expressions that cover all the minterms of the function $F$. They both consist of 4 terms. Finding the absolute minimum number of terms often requires techniques like the Quine-McCluskey algorithm or careful analysis of the K-map for essential prime implicants and selecting non-essential ones optimally. Given that both options represent valid and potentially minimal covers (as they use standard prime implicants and cover all required minterms with a comparable number of terms and literals), and aligning with typical results for such problems, options B and D are considered the minimal forms.

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Important Questions from Karnaugh Maps

  1. The minimized sum of products expression for f(a,b,c,d) = Ʃm(0,1,5,6,7,8,9) with don’t care Ʃm(10,11,12,13,14,15) is ___________.

  2. A problem detector system produces an alarm in the factory when one of the three conditions occurs. The system is designed as such tha only one condition can occur at a time. If the three conditions are defined as q, r, and s respectively, the output logic for the system is given as

  3. The Boolean expression \({\rm{F}}\left( {{\rm{x}},{\rm{y}},{\rm{z}}} \right) = {\rm{\;\bar xy\;\bar z}} + {\rm{\;x\;\bar y\bar z}} + {\rm{\;x\;y\;\bar z}} + {\rm{\;x\;y\;z}}\) is converted into the canonical product of sum (POS) form is

  4. A 3 - input majority gate is defined by the logic function \({\rm{M}}\left( {{\rm{a}},{\rm{b}},{\rm{c}}} \right) = {\rm{\;ab\;}} + {\rm{\;bc\;}} + {\rm{\;ac}}\) .  Which one of the following gate is represented by the function \({\rm{M}}\left( {\overline {{\rm{M}}\left( {{\rm{a}},{\rm{b}},{\rm{c}}} \right)} ,{\rm{\;M}}\left( {{\rm{a}},{\rm{b}},\overline {{\rm{c\;}}} } \right),{\rm{c}}} \right)?\)

  5. In the sum of products function f (X, Y, Z) = ∑ (2, 3, 4, 5) , the prime implicants are

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