The area of a strip of constant width around the Earth depends on its location relative to the equator. The Earth is approximately spherical.
Consider a strip of a fixed width '$w$' running parallel to the equator at a certain latitude '$\phi$'. The area of such a strip is approximately equal to the circumference of the circle of latitude at that point multiplied by the strip's width.
The circumference of a circle of latitude '$\phi$' is given by $C_\phi = 2 \pi R \cos(\phi)$, where '$R$' is the Earth's radius.
Therefore, the area '$A_\phi$' of the strip is approximately:
$ A_\phi \approx C_\phi \times w = (2 \pi R \cos(\phi)) \times w $
Since the width '$w$' (10 m) and the Earth's radius '$R$' are constant, the area '$A_\phi$' is directly proportional to $\cos(\phi)$.
We need to compare the areas of three strips:
The cosine function decreases as the angle increases from $0^\circ$ to $90^\circ$. Therefore:
$ \cos(0^\circ) > \cos(23.5^\circ) > \cos(66.5^\circ) $
This implies:
$ 1 > 0.917 > 0.397 $
Since area is proportional to $\cos(\phi)$, the order of the areas is:
$ A_1 > A_2 > A_3 $
The strip at the Equator has the largest area ($A_1$), followed by the strip at the Tropic of Cancer ($A_2$), and the strip at the Arctic Circle has the smallest area ($A_3$).