Choose the correct statement(s): A. In photoelectric effect, the minimum negative potential to the plate A for which photocurrent is zero is called saturation potential. B. Maximum kinetic energy of photoelectrons is directly proportional to intensity of incident radiation. C. \( K_{\text{max}} = eV_0 \). D. Photocurrent becomes zero at stopping potential. E. For different intensities of light, stopping potential is different. Choose the correct answer from the options given below:
C & D only
- Statement A is incorrect because the potential at which photocurrent stops is called stopping potential, not saturation potential.
- Statement B is incorrect since the maximum kinetic energy of emitted photoelectrons depends on the frequency of light, not its intensity.
- Statement C is correct as per Einstein's photoelectric equation: \( K_{\text{max}} = eV_0 \).
- Statement D is correct because at stopping potential, even the most energetic electrons are unable to reach the anode, making the photocurrent zero.
- Statement E is incorrect because stopping potential depends on frequency, not intensity.
Thus, the correct answer is option 1.
Important Questions from Dual Nature of Radiation and Matter
A point source causing photoelectric emission from a metallic plate is moved away from the plate. The variation of photoelectric current with distance from the source is correctly represented by the graph:
The wavelength of light from the spectral emission line of sodium is 662 nm. The kinetic energy at which an electron would have the same de Broglie wavelength would be: (h=6.62×10−34J⋅s,me=9×10−31kg)
Energy of a photon corresponding to a wavelength of 600 nm is 2.08 eV. The energy of a photon of wavelength 400 nm will be:
A particle moves three times as fast as an electron. The ratio of the de Broglie wavelength of the particle to that of the electron is 1.813 × 10-4. The mass of the particle is:
According to Einstein’s photoelectric equation, the plot of the Kinetic Energy of the emitted photoelectrons from a metal versus the frequency of the incident radiation gives a straight line whose slope:
