A point source causing photoelectric emission from a metallic plate is moved away from the plate. The variation of photoelectric current with distance from the source is correctly represented by the graph:

Photoelectric emission is a phenomenon where electrons are ejected from a metal surface when light of sufficient frequency falls on it. The ejected electrons are called photoelectrons, and the flow of these electrons constitutes the photoelectric current.
The magnitude of the photoelectric current depends on several factors, including the intensity of the incident light, the frequency of the incident light, the material of the metallic plate, and the potential difference between the plate and the collector electrode (if any). In this question, we are considering how the photoelectric current varies with the distance of a point source of light from the metallic plate, assuming other factors remain constant.
For a point source emitting light uniformly in all directions, the intensity of light at a given distance from the source follows the inverse square law. This means that the intensity of light ($I$) is inversely proportional to the square of the distance ($r$) from the source.
Mathematically, this relationship can be expressed as:
$$I \propto \frac{1}{r^2}$$
This implies that as the distance $r$ increases, the intensity $I$ decreases rapidly.
According to the theory of the photoelectric effect, the number of photoelectrons emitted per unit time is directly proportional to the intensity of the incident light, provided the frequency of the light is above the threshold frequency of the metal.
Since the photoelectric current ($J$) is proportional to the number of photoelectrons emitted per unit time, it follows that the photoelectric current is directly proportional to the intensity of the incident light:
$$J \propto I$$
Combining the relationship between light intensity and distance from a point source ($I \propto \frac{1}{r^2}$) with the relationship between photoelectric current and light intensity ($J \propto I$), we can find how the photoelectric current varies with the distance from the point source:
$$J \propto I \propto \frac{1}{r^2}$$
Therefore, the photoelectric current ($J$) is inversely proportional to the square of the distance ($r$) from the point source:
$$J \propto \frac{1}{r^2}$$
We are looking for a graph that shows the photoelectric current decreasing with increasing distance according to the inverse square law ($J \propto 1/r^2$).
Based on our analysis, Graph 3 correctly represents the variation of photoelectric current with the distance from a point source, following the inverse square law for light intensity.
| Concept | Description | Relationship |
|---|---|---|
| Photoelectric Effect | Emission of electrons from a metal when light strikes it. | Triggered by light of sufficient frequency. |
| Photoelectric Current | Flow of photoelectrons. | Proportional to the number of emitted electrons. |
| Light Intensity (Point Source) | Power of light per unit area. | $I \propto \frac{1}{r^2}$ (Inverse Square Law) |
| Photoelectric Current vs. Intensity | How current changes with light brightness. | $J \propto I$ |
| Photoelectric Current vs. Distance (Point Source) | How current changes as source moves away. | $J \propto \frac{1}{r^2}$ |
Besides the distance from a point source, several other factors influence the photoelectric current:
In the context of this question, when only the distance from a point source is varied, the intensity changes, directly impacting the photoelectric current according to the inverse square law.
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