(Note: The odd one out is not based on the number of consonants/vowels or their position in the letter cluster.)
The question requires identifying the letter group that does not follow the pattern established by the other three, based on their alphabetical order.
First, we determine the numerical position of each letter in the English alphabet (A=1, B=2, ..., Z=26).
Let's analyze each option:
Three options form a group based on a common characteristic. Comparing the patterns:
We observe that PLG and WSN share the exact same pattern of differences: $(-4, -5)$.
BXS and DZV share the first difference of $+22$.
However, let's focus on the second difference. Three options (BXS, PLG, WSN) have a second difference of $-5$. DZV has a second difference of $-4$. Therefore, BXS, PLG, and WSN form the group.
The group is formed by the letter clusters where the difference between the second and third letter's alphabetical position is $-5$. These are BXS, PLG, and WSN.
Option DZV does not fit this pattern, as the difference between Z and V is $-4$. Thus, DZV is the odd one out.