Reasoning with Letter Cluster Pairs
The question asks to identify the letter cluster pair that does not follow the same alphabetical relationship as the others. We need to find the pattern connecting the letters within each pair and between the two parts of the pair.
Analyzing Letter Relationships
We will examine the alphabetical position of each letter (A=1, B=2, ..., Z=26) and the difference between corresponding letters in the two parts of each pair.
- Option 1: FN - KS
- F is the 6th letter, N is the 14th letter.
- K is the 11th letter, S is the 19th letter.
- Difference within pairs: N(14) - F(6) = 8; S(19) - K(11) = 8.
- Difference between clusters: K(11) - F(6) = 5; S(19) - N(14) = 5.
- The pattern is a +5 shift from the first cluster (FN) to the second cluster (KS).
- Option 2: HP - NV
- H is the 8th letter, P is the 16th letter.
- N is the 14th letter, V is the 22nd letter.
- Difference within pairs: P(16) - H(8) = 8; V(22) - N(14) = 8.
- Difference between clusters: N(14) - H(8) = 6; V(22) - P(16) = 6.
- The pattern is a +6 shift from the first cluster (HP) to the second cluster (NV).
- Option 3: CK - IQ
- C is the 3rd letter, K is the 11th letter.
- I is the 9th letter, Q is the 17th letter.
- Difference within pairs: K(11) - C(3) = 8; Q(17) - I(9) = 8.
- Difference between clusters: I(9) - C(3) = 6; Q(17) - K(11) = 6.
- The pattern is a +6 shift from the first cluster (CK) to the second cluster (IQ).
- Option 4: GO - MU
- G is the 7th letter, O is the 15th letter.
- M is the 13th letter, U is the 21st letter.
- Difference within pairs: O(15) - G(7) = 8; U(21) - M(13) = 8.
- Difference between clusters: M(13) - G(7) = 6; U(21) - O(15) = 6.
- The pattern is a +6 shift from the first cluster (GO) to the second cluster (MU).
Identifying the Odd One Out
Options 2, 3, and 4 exhibit a consistent pattern where the second cluster's letters are shifted +6 positions forward in the alphabet compared to the first cluster's corresponding letters.
Option 1, however, shows a shift of only +5 positions between the clusters (F to K, and N to S).
Therefore, the pair FN - KS does not belong to the group.
Important Questions from Classification (Notes)
- Find the odd one out
- Find the odd one out:
- Based on the English alphabetical order, three of the following four are alike in a certain way and thus form a group. Which is the one that does not belong to that group?
(Note: The odd one out is not based on the number of consonants/vowels or their position in the letter cluster.) - Based on the alphabetical order, three of the following four are alike in a certain way and thus form a group. Which one does not belong to that group?
(Note: The odd one out is not based on the number of consonants or vowels or their position in the letter cluster) - Based on the English alphabetical order, three of the following four letter-clusters are alike in a certain way and thus form a group. Which letter-cluster DOES NOT belong to that group?
(Note: The odd one out is not based on the number of consonants/vowels or their position in the letter-cluster.)
