Based on the data in table, answer the five questions that follow: The following table shows the break‐up of population in terms of males, females and transgenders of five different cities A ‐ E. Some of the data in the table is in percent (%) while some data is in numbers. City‐wise Break‐up of Population Population of City 'C' is what percent less than the population of City 'B'?City Population Break-up Males Females Transgenders A 45% 30% 2000 B 50% 3000 35% C 8000 35% 15% D 45% 3600 25% E 38% 32% 4200
20%
The question asks us to find the percentage difference between the population of City 'C' and City 'B' based on the provided data table. To do this, we first need to calculate the total population for both City 'C' and City 'B' using the given percentages and numbers.
| City | Population Break-up | Males | Females | Transgenders |
|---|---|---|---|---|
| A | 45% | 30% | 2000 | |
| B | 50% | 3000 | 35% | |
| C | 8000 | 35% | 15% | |
| D | 45% | 3600 | 25% | |
| E | 38% | 32% | 4200 |
In City C, we are given the number of males and the percentages of females and transgenders.
The total percentage of Females and Transgenders in City C is:
\( \text{Percentage of Females + Percentage of Transgenders} = 35\% + 15\% = 50\% \)
This means the remaining population, which are the males, constitute the rest of the percentage:
\( \text{Percentage of Males} = 100\% - 50\% = 50\% \)
So, 50% of the total population of City C is equal to 8000. We can use this to find the total population of City C.
Let the total population of City C be \(P_C\). Then:
\( 50\% \text{ of } P_C = 8000 \)
\( 0.50 \times P_C = 8000 \)
\( P_C = \frac{8000}{0.50} \)
\( P_C = 16000 \)
The total population of City C is 16000.
In City B, we are given the number of females and the percentages of males and transgenders.
The total percentage of Males and Transgenders in City B is:
\( \text{Percentage of Males + Percentage of Transgenders} = 50\% + 35\% = 85\% \)
This means the remaining population, which are the females, constitute the rest of the percentage:
\( \text{Percentage of Females} = 100\% - 85\% = 15\% \)
So, 15% of the total population of City B is equal to 3000. We can use this to find the total population of City B.
Let the total population of City B be \(P_B\). Then:
\( 15\% \text{ of } P_B = 3000 \)
\( 0.15 \times P_B = 3000 \)
\( P_B = \frac{3000}{0.15} \)
\( P_B = 20000 \)
The total population of City B is 20000.
Now we need to find out what percentage less is the population of City C compared to the population of City B. The formula for percentage less is:
\( \text{Percentage Less} = \frac{\text{Value 1} - \text{Value 2}}{\text{Value 1}} \times 100 \)
In this case, Value 1 is the population of City B (20000) and Value 2 is the population of City C (16000).
Difference in population = Population of City B - Population of City C
\( \text{Difference} = 20000 - 16000 = 4000 \)
Now, calculate the percentage less:
\( \text{Percentage Less} = \frac{\text{Difference}}{\text{Population of City B}} \times 100 \)
\( \text{Percentage Less} = \frac{4000}{20000} \times 100 \)
\( \text{Percentage Less} = \frac{4}{20} \times 100 \)
\( \text{Percentage Less} = \frac{1}{5} \times 100 \)
\( \text{Percentage Less} = 0.20 \times 100 \)
\( \text{Percentage Less} = 20\% \)
The population of City C is 20% less than the population of City B.
| City | Given Data Used | Calculation for Total Population | Total Population |
|---|---|---|---|
| C | Males: 8000 Females: 35%, Transgenders: 15% |
50% = 8000 \(P_C = 8000 / 0.50\) |
16000 |
| B | Females: 3000 Males: 50%, Transgenders: 35% |
15% = 3000 \(P_B = 3000 / 0.15\) |
20000 |
| Comparison C vs B | \(P_C = 16000\) \(P_B = 20000\) |
\(\frac{P_B - P_C}{P_B} \times 100 = \frac{20000-16000}{20000} \times 100\) | 20% less |
Data interpretation questions often involve tables, charts, and graphs that require careful reading and calculation. Key concepts used here include:
These skills are crucial for solving quantitative aptitude problems based on data sets like this population break-up table.
The table shows District-wise data of a number of primary school teachers posted in schools of a city.
Study the table and answer the question:
District | Male teachers | Female teachers |
East | 1650 | 2375 |
North | 1075 | 2651 |
West | 1280 | 1520 |
South | 1170 | 1085 |
Central | 690 | 859 |
Table shows income (in Rs. ) received by 4 employees of a company during the month of December 2020 and all their income sources.
Source | Amit | Suresh | Nitin | Varun |
Salary | 35000 | 38500 | 29000 | 42000 |
Arrears | 6000 | 6300 | 5000 | 7500 |
Bonus | 1000 | 1100 | 1000 | 1240 |
Overtime | 1800 | 1950 | 1400 | 1500 |
Study the table and answer the question:
Income (Rs.) | No. of persons |
Less than 200 | 12 |
Less than 250 | 26 |
Less than 300 | 34 |
Less than 350 | 40 |
Less than 400 | 50 |
The following table shows the annual profit of a company (in Rs. lakh).
2014-2015 | 2015-2016 | 2016-0217 | 2017-2018 | 2018-2019 |
625 | 690 | 725 | 775 | 815 |
The period which has the maximum percentage increase in profit over the previous year is:
The table given below shows the number of persons participating in a survey from 6 different states.
| States | Persons |
| S1 | 100 |
| S2 | 200 |
| S3 | 400 |
| S4 | 500 |
| S5 | 600 |
| S6 | 800 |
What is the ratio of number of person participating in a survey from state S3 to the number of person participating in a survey from state S4?