The problem asks for the annual simple interest rate (R) when a sum of money becomes 5 times itself in 15 years.
Let the principal amount be P.
The amount becomes 5 times, so the final Amount (A) = 5P.
The Simple Interest (SI) earned is the difference between the Amount and the Principal:
SI = A - P = 5P - P = 4P
The time period (T) is given as 15 years.
The formula for Simple Interest is:
\begin{equation} SI = \frac{P \times R \times T}{100} \end{equation}
We know SI = 4P and T = 15 years. Substitute these values into the formula:
\begin{equation} 4P = \frac{P \times R \times 15}{100} \end{equation}
Divide both sides by P (assuming P ≠ 0):
\begin{equation} 4 = \frac{R \times 15}{100} \end{equation}
Rearrange the equation to solve for R:
\begin{equation} R = \frac{4 \times 100}{15} \end{equation}
\begin{equation} R = \frac{400}{15} \end{equation}
Calculate the value:
\begin{equation} R = \frac{80}{3} \approx 26.666... \end{equation}
Rounding to two decimal places, the rate is 26.67%.
The required simple interest rate is 26.67% per year.
Anil lent a sum of Rs. 5,000 on simple interest for 10 years in such a way that the rate of interest is 6% per annum for the first 2 years, 8% per anmum for the next 2 years and 10% per annum beyond 4 years. How much interest (in Rs.) will he earn at the end of 10 years?
What will be the simple interest on a sum of Rs. 12000 at the rate of 15 percent per annum for three years ?
If in 13 years fixed sum doubles at simple interest, what will be the interest rate per year? (correct to two decimal places)
On simple interest a sum of Rs. 640 becomes Rs. 832 in 2 years. What will Rs. 860 become in 4 years at the same rate of simple interest?
A certain sum amounts to Rs. 81840 in 3 years and to Rs. 92400 in 5 years at x% p.a. under simple interest. If the rate of interest is becomes (x + 2)%, then in how many years will the same sum double itself?