The problem asks for the annual simple interest rate (R) when a sum of money becomes 5 times itself in 15 years.
Let the principal amount be P.
The amount becomes 5 times, so the final Amount (A) = 5P.
The Simple Interest (SI) earned is the difference between the Amount and the Principal:
SI = A - P = 5P - P = 4P
The time period (T) is given as 15 years.
The formula for Simple Interest is:
\begin{equation} SI = \frac{P \times R \times T}{100} \end{equation}
We know SI = 4P and T = 15 years. Substitute these values into the formula:
\begin{equation} 4P = \frac{P \times R \times 15}{100} \end{equation}
Divide both sides by P (assuming P ≠ 0):
\begin{equation} 4 = \frac{R \times 15}{100} \end{equation}
Rearrange the equation to solve for R:
\begin{equation} R = \frac{4 \times 100}{15} \end{equation}
\begin{equation} R = \frac{400}{15} \end{equation}
Calculate the value:
\begin{equation} R = \frac{80}{3} \approx 26.666... \end{equation}
Rounding to two decimal places, the rate is 26.67%.
The required simple interest rate is 26.67% per year.
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A sum of Rs.1200 becomes Rs.1560 at a rate of simple interest in 3 years. In how many years will the sum of Rs.800 amount to Rs.1120 at the same rate of simple interest?