Let S be Sharad's present age, Son be his son's present age, and D be his daughter's present age.

Establishing Present Age Relationships

• According to the question, Sharad is three times as old as his son:

  $S = 3 \times Son$

• The daughter is 3 years younger than the son:

  $D = Son - 3$

Calculating Ages 3 Years Ago

The ages of the three people 3 years ago would be:

• Sharad's age: $S - 3$
• Son's age: $Son - 3$
• Daughter's age: $D - 3$

Using the Sum of Past Ages

The sum of their ages 3 years ago was 63 years:

$(S - 3) + (Son - 3) + (D - 3) = 63$

Simplify the equation:

$S + Son + D - 9 = 63$

Combine the ages to find the total present age sum:

$S + Son + D = 63 + 9$

$S + Son + D = 72$

Solving for Sharad's Present Age

Substitute the relationships from step 1 into the total present age sum equation:

$(3 \times Son) + Son + (Son - 3) = 72$

Combine the terms involving the son's age:

$5 \times Son - 3 = 72$

Add 3 to both sides to isolate the son's age term:

$5 \times Son = 72 + 3$

$5 \times Son = 75$

Divide by 5 to find the son's present age:

$Son = \frac{75}{5}$

$Son = 15$

Now, calculate Sharad's present age using the relationship $S = 3 \times Son$:

$S = 3 \times 15$

$S = 45$

Therefore, Sharad's present age is 45 years.