If 30 molecules of glucose-6-phosphate enter this pathway, and you randomly draw one molecule from the products of the pathway, the probability that this molecule is NADPH is __________ (round off to one decimal place).
To solve this problem, we need to determine the probability of randomly selecting a NADPH molecule from the total products produced when 30 molecules of glucose-6-phosphate enter the oxidative branch of the pentose phosphate pathway. Each glucose-6-phosphate molecule generates:
- 2 NADPH
- 1 $\text{CO}_2$
- 1 ribulose-5-phosphate
Thus, for 30 glucose-6-phosphate molecules, we have:
- Total NADPH molecules: \(30 \times 2 = 60\)
- Total $\text{CO}_2$ molecules: 30
- Total ribulose-5-phosphate molecules: 30
The total number of molecules produced is the sum of all products: \(60 + 30 + 30 = 120\). The probability of selecting a NADPH molecule is the ratio of NADPH molecules to the total number of molecules: \[P(\text{NADPH}) = \frac{60}{120} = 0.5\]This calculated probability is 0.5, which falls within the expected range of 0.5 to 0.5. Therefore, the probability that a randomly selected molecule is NADPH is 0.5.
Important Questions from Metabolism Glycolysis Nucleotide
- The oxidative phase of the hexose monophosphate pathway generates ________ moles of NADPH per mole of glucose 6-phosphate (answer in integer).
- Which one of the following enzymes is NOT inhibited by glucose-6-phosphate?
- Match the hormones in Group I with their metabolic precursor in Group II
Group I Group II P. 17-$\beta$ estradiol 1. Arachidonic acid Q. Thromboxane A2 2. Tyrosine R. Epinephrine 3. $\beta$-carotene S. Retinoic acid 4. Cholesterol Which of the following statements are TRUE for respiration?
P. The conversion of one molecule of pyruvate to three molecules of $CO_2$ generates four molecules of NADH
Q. Fructose 6-phospate is the principal substrate for glycolysis
R. The oxidation of glucose 6-phosphate to 6-phosphogluconate is the first step in the oxidative pentose phosphate pathway
S. The mitochondrial 'alternative oxidase' provides an alternative pathway for transfer of electrons from ubiquinone to oxygen utilizing proton pumping complex of the respiratory chain
- Phosphoglucose isomerase was incubated with 0.2 M of glucose 6-phosphate. On reaching equilibrium, 55% of glucose 6-phosphate was converted to fructose 6-phosphate. The equilibrium constant for this reaction is ________.
