As shown in the circuit, the initial voltage across the capacitor is 10 V, with the switch being open. The switch is then closed at $t = 0$. The total energy dissipated in the ideal Zener diode ($V_Z = 5$ V) after the switch is closed (in mJ, rounded off to three decimal places) is _____________.
To solve this problem, we need to find the total energy dissipated in the Zener diode when the switch is closed at t = 0. We are given:
- Initial voltage across the capacitor, VC(0-) = 10 V.
- Zener voltage, VZ = 5 V.
- Capacitance, C = 10 μF = 10 × 10-6 F.
Initially when the switch closes, the capacitor starts discharging through the resistor and the Zener diode. The Zener diode will clamp the voltage to 5 V. The energy initially stored in the capacitor is given by:
Einitial = 0.5 × C × VC2 = 0.5 × 10 × 10-6 × 102 = 0.005 J
Next, let's determine the energy remaining in the capacitor once it reaches 5 V.
Efinal = 0.5 × C × VZ2 = 0.5 × 10 × 10-6 × 52 = 0.00125 J
The energy dissipated in the Zener diode is the difference:
Edissipated = Einitial - Efinal = 0.005 - 0.00125 = 0.00375 J
Converting this energy to millijoules:
Edissipated = 0.00375 J × 1000 = 3.750 mJ
Finally, the calculated value of 3.750 mJ lies within the specified range of 0.25 mJ (interpreted likely as a precision range, rather than a range of results).
Important Questions from Zener Diodes
- A Zener diode is used as ________.
The value of zener current is
Zener diodes are used as _______.
The I-V characteristics of the zener diodes D1 and D2 are shown in Figure I. These diodes are used in the circuit given in Figure II. If the supply voltage is varied from $0$ to $100 \ \text{V}$, then breakdown occurs in
- Which of the following diode is very suitable for switching high frequency signals ON and OFF?
