(A) The simple interest on Rs 6600 at 5% per annum for 2 yrs.
(B) The simple interest on Rs 200 at 6% per annum for 5 yrs.
(C) The simple interest on Rs 840 at 5% per annum for 4 yrs.
(D) The simple interest on Rs 5000 at 12% per annum for 2 yrs.
Choose the correct answer from the options given below:
To determine the correct order of simple interest for the given cases, we must first calculate the simple interest (SI) for each scenario. The formula for simple interest is:
$SI = \frac{P \times R \times T}{100}$
Where:
For Case (A), the details are:
Using the formula:
$SI_A = \frac{6600 \times 5 \times 2}{100} = \frac{6600}{100} \times 10 = 66 \times 10 = 660$
So, the simple interest for Case (A) is Rs 660.
For Case (B), the details are:
Using the formula:
$SI_B = \frac{200 \times 6 \times 5}{100} = \frac{200}{100} \times 30 = 2 \times 30 = 60$
So, the simple interest for Case (B) is Rs 60.
For Case (C), the details are:
Using the formula:
$SI_C = \frac{840 \times 5 \times 4}{100} = \frac{840 \times 20}{100} = \frac{16800}{100} = 168$
So, the simple interest for Case (C) is Rs 168.
For Case (D), the details are:
Using the formula:
$SI_D = \frac{5000 \times 12 \times 2}{100} = \frac{5000}{100} \times 24 = 50 \times 24 = 1200$
So, the simple interest for Case (D) is Rs 1200.
After calculating the simple interest for all four cases, we can compare the values:
| Case | Simple Interest (Rs) |
|---|---|
| (A) | 660 |
| (B) | 60 |
| (C) | 168 |
| (D) | 1200 |
The question asks to arrange the simple interest amounts in decreasing order, which means from the largest amount to the smallest amount. Based on the calculated values:
Therefore, the simple interest of the cases in decreasing order is (D), (A), (C), (B).
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A sum of Rs.1200 becomes Rs.1560 at a rate of simple interest in 3 years. In how many years will the sum of Rs.800 amount to Rs.1120 at the same rate of simple interest?