The problem asks for the calculation of simple interest paid by Anisha.
Given Information
- Principal Amount (P) = ₹28,260
- Rate of Interest (R) = 9% per annum
- Time Period (T) = 9 months
Interest Calculation Steps
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Convert the time period from months to years:
Time (T) = 9 months = $\frac{9}{12}$ years = $\frac{3}{4}$ years = 0.75 years
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Use the formula for Simple Interest (SI):
$SI = \frac{P \times R \times T}{100}$
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Substitute the given values into the formula:
$SI = \frac{28260 \times 9 \times 0.75}{100}$
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Calculate the interest:
$SI = \frac{28260 \times 6.75}{100}$
$SI = \frac{190755}{100}$
$SI = 1907.55$
Final Interest Paid
The total simple interest Anisha paid is ₹1907.55.
Important Questions from Simple Interest
Anil lent a sum of Rs. 5,000 on simple interest for 10 years in such a way that the rate of interest is 6% per annum for the first 2 years, 8% per anmum for the next 2 years and 10% per annum beyond 4 years. How much interest (in Rs.) will he earn at the end of 10 years?
What will be the simple interest on a sum of Rs. 12000 at the rate of 15 percent per annum for three years ?
If in 13 years fixed sum doubles at simple interest, what will be the interest rate per year? (correct to two decimal places)
On simple interest a sum of Rs. 640 becomes Rs. 832 in 2 years. What will Rs. 860 become in 4 years at the same rate of simple interest?
A certain sum amounts to Rs. 81840 in 3 years and to Rs. 92400 in 5 years at x% p.a. under simple interest. If the rate of interest is becomes (x + 2)%, then in how many years will the same sum double itself?
