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Question

Anisha borrowed ₹28,260 from her friend at 9% per annum, simple interest. She returned the amount after 9 months. How much interest did she pay?

The correct answer is
₹ 1907.55

The problem asks for the calculation of simple interest paid by Anisha.

Given Information

  • Principal Amount (P) = ₹28,260
  • Rate of Interest (R) = 9% per annum
  • Time Period (T) = 9 months

Interest Calculation Steps

  1. Convert the time period from months to years:

    Time (T) = 9 months = $\frac{9}{12}$ years = $\frac{3}{4}$ years = 0.75 years

  2. Use the formula for Simple Interest (SI):

    $SI = \frac{P \times R \times T}{100}$

  3. Substitute the given values into the formula:

    $SI = \frac{28260 \times 9 \times 0.75}{100}$

  4. Calculate the interest:

    $SI = \frac{28260 \times 6.75}{100}$

    $SI = \frac{190755}{100}$

    $SI = 1907.55$

Final Interest Paid

The total simple interest Anisha paid is ₹1907.55.

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Important Questions from Simple Interest

  1. If ₹12,800 is invested in a bank for 5 years at the rate of 9% per annum simple interest. what amount is returned by the bank?

  2. Somu has borrowed ₹10,000 from a money lender with simple interest at a rate of 7% half yearly. How much amount will he pay to the money lender after 3 years?

  3. Find the Simple interest on Rs. 2,400 from 20 March 2019 to 31 may 2019 at \(6{1 \over 4}\) % rate?

  4. If the simple interest for five years is equal is 35% of the principal, that rate of interest is:

  5. A sum fetched a simple interest of Rs. 3,040 at the rate of 8% p.a in 5 years. what is the sum?

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