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Question

An infinite number of identical circular discs each of radius $\frac{1}{2}$ are tightly packed such that the centres of the discs are at integer values of coordinates x and y. The ratio of the area of the uncovered patches to the total area is

The correct answer is
$1 - \pi/4$

Packing Circular Discs: Area Calculation

This solution calculates the ratio of uncovered area to total area for discs packed on an integer coordinate grid.

Analyzing the Disc Packing

We are given identical circular discs, each with a radius $r = \frac{1}{2}$. The centers of these discs are located at all integer coordinate points $(x, y)$, such as $(0,0), (1,0), (0,1), (1,1)$, and so on. Let's focus on a single unit square cell in the coordinate plane, for example, the square with vertices at $(0,0), (1,0), (1,1), (0,1)$. The area of this unit square is $A_{cell} = 1 \times 1 = 1$.

Calculating Covered Area in the Unit Cell

Within this unit square cell, portions of four discs centered at its corners contribute to the covered area. These discs are centered at $(0,0), (1,0), (0,1),$ and $(1,1)$.

  • The area of one complete disc is calculated using the formula $A_{disc} = \pi r^2$. With $r = \frac{1}{2}$, the area is $A_{disc} = \pi (\frac{1}{2})^2 = \frac{\pi}{4}$.
  • The portion of each disc that lies within the unit square cell is exactly a quarter-circle, as the center is at a corner and the radius is $\frac{1}{2}$.
  • The area of one quarter-circle segment within the square is $\frac{1}{4} A_{disc} = \frac{1}{4} \times \frac{\pi}{4} = \frac{\pi}{16}$.
  • Since four such quarter-circles (one from each of the four corner discs) lie within the unit square, the total area covered by the discs inside this cell is the sum of these four segments: $ A_{covered} = 4 \times \frac{\pi}{16} = \frac{\pi}{4} $

Finding the Uncovered Area Ratio

The total area of the unit cell is $A_{cell} = 1$. The area covered by the discs within this cell is $A_{covered} = \frac{\pi}{4}$. The area of the uncovered patches within the unit cell is the difference between the total cell area and the covered area: $ A_{uncovered} = A_{cell} - A_{covered} = 1 - \frac{\pi}{4} $ The ratio of the uncovered area to the total area is: $ \text{Ratio} = \frac{A_{uncovered}}{A_{cell}} = \frac{1 - \frac{\pi}{4}}{1} = 1 - \frac{\pi}{4} $

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Important Questions from Mensuration 2D (Notes)

  1. A 2 cm wide wooden strip is to be fixed on a photo of 40 cm x 30 cm size all along its four sides. What is the minimum length of the wooden strip required?
  2. $110$ मी. $\times 60$ मी. घास-आच्छादित आयताकार प्लॉट के अंदर चारों ओर $2$ मी. चौड़ा बजरी का रास्ता बनाना है। $₹2$ प्रति वर्ग मी. की दर से बजरी बिछाने का लागत ज्ञात कीजिए।
  3. The perimeter of a square is $596$ m. Its area (in m$^2$) is:
  4. A hollow spherical shell is made of a metal of density 4 g/cm$^3$. Its internal and external radius are 15 cm and 18 cm, respectively. What is the weight (in kg) of the shell?
    (Use $\pi = \frac{22}{7}$ and Density = $\frac{\text{Mass}}{\text{Volume}}$)
  5. Water flows out through a circular pipe whose internal diameter is 2 cm, at the rate of 4 metres per second into a cylindrical tank, the radius of whose base is 80 cm. By how much will the level of water rise in 16 minutes?
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