All Exams Test series for 1 year @ ₹349 only
Question

An electric bulb is connected to a 200 V generator. The current drawn by the bulb is 0.1 A. What is the power of the bulb?

The correct answer is

20 W

Power (P) is given by the formula: P = V × I
P = 200 V × 0.1 A
P = 20 W.

Was this answer helpful?

Important Questions from Power in Electric Circuits

  1. An electric bulb is connected to 220 V generator. The current drawn is 600 mA. What is the power of the bulb?

  2. What is the current required to light a 60 W incandescent bulb in a domestic supply of 240 V ?
  3. What is the power factor for a purely inductive or purely capacitive AC circuit?

  4. Convert $1 \text{ MWh}$ (megawatt-hour) into Joules.

  5. Two incandescent bulbs are rated at $P_1 = 200\,\text{W}$ and $P_2 = 100\,\text{W}$, respectively, when operated at a voltage of $V_{rated} = 220\,\text{V}$. If these two bulbs are connected in series across a $V_{supply} = 110\,\text{V}$ DC power supply, determine which bulb will glow brighter and by what factor compared to the other bulb.
Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App