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Question

An electric bulb is connected to a 200 V generator. The current drawn by the bulb is 0.1 A. What is the power of the bulb?

The correct answer is

20 W

Power (P) is given by the formula: P = V × I
P = 200 V × 0.1 A
P = 20 W.

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Important Questions from Power in Electric Circuits

  1. What is the power factor for a purely inductive or purely capacitive AC circuit?

  2. Convert $1 \text{ MWh}$ (megawatt-hour) into Joules.

  3. Two incandescent bulbs are rated at $P_1 = 200\,\text{W}$ and $P_2 = 100\,\text{W}$, respectively, when operated at a voltage of $V_{rated} = 220\,\text{V}$. If these two bulbs are connected in series across a $V_{supply} = 110\,\text{V}$ DC power supply, determine which bulb will glow brighter and by what factor compared to the other bulb.
  4. Two electric bulbs are rated '$220$ V, $100$ W' and '$220$ V, $50$ W' respectively.
    If these two bulbs are connected in series across a $220$ V supply, what will be the power consumed by the $100$ W bulb?
  5. The charge flowing through a resistance $R$ varies with time $t$ as $Q = At^2 - Bt^3$, where $A$ and $B$ are positive constants. The total heat produced in $R$ until the current becomes zero is:
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