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Question

An ant starts at the origin and moves along the $y$-axis and covers a distance $l$. This is its first stage in its journey. Every subsequent stage requires the ant to turn right and move a distance which is half of its previous stage. What would be its coordinates at the end of its $5^{\text{th}}$ stage?

The correct answer is
$\left(\frac{3l}{8}, \frac{13l}{16}\right)$

Ant Movement Calculation

The problem asks for the coordinates of an ant after completing 5 stages of movement, starting from the origin.

Stage-by-Stage Coordinate Tracking

The ant's movement follows a pattern: initial movement along the y-axis, followed by subsequent stages involving a right turn and movement covering half the previous distance.

  • Stage 1: Starts at origin $(0, 0)$. Moves along the positive $y$-axis for distance $l$.
    • Coordinates: $(0, l)$
    • Direction: Positive $y$-axis
  • Stage 2: Turns right from positive $y$-axis (moves along positive $x$-axis). Distance is $l/2$.
    • Starting coordinates: $(0, l)$
    • Movement: $(l/2, 0)$
    • Final coordinates: $(0 + l/2, l) = (\frac{l}{2}, l)$
    • Direction: Positive $x$-axis
  • Stage 3: Turns right from positive $x$-axis (moves along negative $y$-axis). Distance is $(l/2)/2 = l/4$.
    • Starting coordinates: $(\frac{l}{2}, l)$
    • Movement: $(0, -l/4)$
    • Final coordinates: $(\frac{l}{2}, l - \frac{l}{4}) = (\frac{l}{2}, \frac{3l}{4})$
    • Direction: Negative $y$-axis
  • Stage 4: Turns right from negative $y$-axis (moves along negative $x$-axis). Distance is $(l/4)/2 = l/8$.
    • Starting coordinates: $(\frac{l}{2}, \frac{3l}{4})$
    • Movement: $(-l/8, 0)$
    • Final coordinates: $(\frac{l}{2} - \frac{l}{8}, \frac{3l}{4}) = (\frac{4l}{8} - \frac{l}{8}, \frac{3l}{4}) = (\frac{3l}{8}, \frac{3l}{4})$
    • Direction: Negative $x$-axis
  • Stage 5: Turns right from negative $x$-axis (moves along positive $y$-axis). Distance is $(l/8)/2 = l/16$.
    • Starting coordinates: $(\frac{3l}{8}, \frac{3l}{4})$
    • Movement: $(0, l/16)$
    • Final coordinates: $(\frac{3l}{8}, \frac{3l}{4} + \frac{l}{16}) = (\frac{3l}{8}, \frac{12l}{16} + \frac{l}{16}) = (\frac{3l}{8}, \frac{13l}{16})$
    • Direction: Positive $y$-axis

Final Coordinates

At the end of the 5th stage, the ant's coordinates are $(\frac{3l}{8}, \frac{13l}{16})$.

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Important Questions from Progression (Notes)

  1. The sum of 16 terms of the series $\sqrt{2} + \sqrt{8} + \sqrt{18} + \sqrt{32} + .....$ is :
  2. The $5^{\text{th}}$ and $9^{\text{th}}$ terms of an arithmetic progression are 7 and 13 respectively. What is the $15^{\text{th}}$ term?
  3. Find the sum of the G.P.:
    $5/11, 5/121, 5/1331, 5/14641, ...$ to $n$ terms.
  4. The value of $1 + (\frac{1}{2^1} + \frac{1}{3}) + (\frac{1}{2^2} + \frac{1}{5} + \frac{1}{6} + \frac{1}{7}) + ... + (\frac{1}{2^9} + ... + \frac{1}{1023})$ lies between

  5. A ball is dropped from a height of 100 m. The ball after each bounce rises vertically by half its previous height (This means at the first bounce it rises by 50 m, by 25 m at the second bounce and so on). What is the vertical distance travelled by the ball between the first and the fifth bounces?
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