Ant Movement Calculation
The problem asks for the coordinates of an ant after completing 5 stages of movement, starting from the origin.
Stage-by-Stage Coordinate Tracking
The ant's movement follows a pattern: initial movement along the y-axis, followed by subsequent stages involving a right turn and movement covering half the previous distance.
- Stage 1: Starts at origin $(0, 0)$. Moves along the positive $y$-axis for distance $l$.
- Coordinates: $(0, l)$
- Direction: Positive $y$-axis
- Stage 2: Turns right from positive $y$-axis (moves along positive $x$-axis). Distance is $l/2$.
- Starting coordinates: $(0, l)$
- Movement: $(l/2, 0)$
- Final coordinates: $(0 + l/2, l) = (\frac{l}{2}, l)$
- Direction: Positive $x$-axis
- Stage 3: Turns right from positive $x$-axis (moves along negative $y$-axis). Distance is $(l/2)/2 = l/4$.
- Starting coordinates: $(\frac{l}{2}, l)$
- Movement: $(0, -l/4)$
- Final coordinates: $(\frac{l}{2}, l - \frac{l}{4}) = (\frac{l}{2}, \frac{3l}{4})$
- Direction: Negative $y$-axis
- Stage 4: Turns right from negative $y$-axis (moves along negative $x$-axis). Distance is $(l/4)/2 = l/8$.
- Starting coordinates: $(\frac{l}{2}, \frac{3l}{4})$
- Movement: $(-l/8, 0)$
- Final coordinates: $(\frac{l}{2} - \frac{l}{8}, \frac{3l}{4}) = (\frac{4l}{8} - \frac{l}{8}, \frac{3l}{4}) = (\frac{3l}{8}, \frac{3l}{4})$
- Direction: Negative $x$-axis
- Stage 5: Turns right from negative $x$-axis (moves along positive $y$-axis). Distance is $(l/8)/2 = l/16$.
- Starting coordinates: $(\frac{3l}{8}, \frac{3l}{4})$
- Movement: $(0, l/16)$
- Final coordinates: $(\frac{3l}{8}, \frac{3l}{4} + \frac{l}{16}) = (\frac{3l}{8}, \frac{12l}{16} + \frac{l}{16}) = (\frac{3l}{8}, \frac{13l}{16})$
- Direction: Positive $y$-axis
Final Coordinates
At the end of the 5th stage, the ant's coordinates are $(\frac{3l}{8}, \frac{13l}{16})$.