Among Si3N4, α-BN, AlN and (SN)x, the compound with the highest conductivity is
(SN)x
Conductivity of Materials
The question asks us to identify the compound with the highest conductivity among Si3N4, α-BN, AlN, and (SN)x. To answer this, we need to consider the electrical conductivity properties of each substance.
Analyzing Conductivity Properties
- Si3N4 (Silicon Nitride): Silicon nitride is a ceramic material widely known for its excellent mechanical and thermal properties. It is also a very good electrical insulator. Insulators have very low electrical conductivity because their electrons are tightly bound and cannot easily move to carry current.
- α-BN (α-Boron Nitride): α-Boron nitride (hexagonal boron nitride) is structurally similar to graphite but is chemically inert and electrically insulating. Like silicon nitride, it has a large bandgap, making it an excellent electrical insulator.
- AlN (Aluminium Nitride): Aluminium nitride is another ceramic material. While it is known for its high thermal conductivity, it is a wide bandgap semiconductor and acts as an excellent electrical insulator at room temperature. Its electrical conductivity is very low compared to conductors.
- (SN)x (Poly(sulfur nitride) or Polythiazyl): This is a unique inorganic polymer. Unlike most polymers which are electrical insulators, (SN)x exhibits metallic conductivity. It is conductive along the polymer chains and is even superconducting at very low temperatures (below 0.3 K). Its conductivity is comparable to that of some metals.
Comparing the four compounds:
Si3N4, α-BN, and AlN are all electrical insulators or semiconductors with very low conductivity. (SN)x, on the other hand, is a metallic conductor.
Therefore, the compound with the highest conductivity among the given options is (SN)x.
Important Questions from p - Block
Which of the following has the lowest boiling point?
Which of the following reaction(s) do(es) NOT occur
(i) [NPCl2]3 + 6 NaF \(\rm \xrightarrow[reflux]{MeCN}\) [NPF2]3 + 6 NaCl
(ii) n PCl5 + n NH4Cl \(\rm \xrightarrow[reflux]{C_6H_5Cl}\) [NPCl2]n + 4 n HCl [n = 3, 4, 5]
(iii) n PF 5 + n NH 4 F \(\rm \xrightarrow[reflux]{C_6H_5Cl}\) [NPF 2 ] n + 4 n HF [n = 3, 4, 5]
Choose the correct statement(s) from the following:
(i) The trend in Lewis acidity among silicon halides is SiI4 < SiBr4 < SiCl4 < SiF4.
(ii) Tin(II) chloride can act as a Lewis acid and not as a Lewis base.
(iii) Aluminosilicates can display Brønsted acidity.
Consider following statements
A. PbCl2 has low solubility in water.
B. Sulfides of As(III) and Sb(III) are soluble in ammonium sulfide.
C. SnS is soluble in yellow ammonium sulfide.
D. MnS is precipitated by passing H2S through acidic MnCl2.
Correct statements are
Which of the statements (A‐D) given below are correct for B2H6 molecule:
A. Addition of Et2O•BF3 to NaBH4 in a polyether solvent produces B2H6.
B. It has D2d symmetry.
C. Reaction of B2H6 with NMe3 gives Me3N•BH3.
D. It is diamagnetic.
