Alkali metals are the elements found in Group 1 of the periodic table. This group includes Lithium (Li), Sodium (Na), Potassium (K), Rubidium (Rb), Cesium (Cs), and Francium (Fr). A key characteristic of these metals is their high reactivity, which stems from having a single electron in their outermost energy shell (general electronic configuration: $ns^1$).
Reducing power is a measure of how easily a substance can donate electrons to another substance. A substance with high reducing power is easily oxidized itself. For alkali metals, this means they readily lose their single valence electron to form a positive ion (cation), typically $M^+$. The reaction is:
$M \rightarrow M^+ + e^-$
To understand the trend in reducing power, let's look at related properties:
Because it becomes easier to lose an electron as you go down the group, the reducing power of alkali metals increases from top to bottom.
Conversely, alkali metals have very little tendency to gain electrons. Therefore, they are very weak oxidizing agents. While their standard electrode potentials ($E^0$) show some variation, their primary chemical characteristic is their strong reducing nature.
Based on the decreasing ionization energy and increasing atomic size down the group, the ability of alkali metals to lose electrons (their reducing power) increases. Therefore, the correct statement is that the reducing power increases from top to bottom.
Consider the following pairs of compounds.
(i) NH4Cl and FeO
(ii) H3N∙BF3 and BCl3
(iii) HSO3F and HF
The more acidic species in (i), (ii) and (iii) are, respectively
Which of the following has the lowest boiling point?
Choose the equilibria from the following that are NOT favoured to go to right:
(A) As2S5 + 5HgO ⇌ As2O5 + 5 HgS
(B) La2(CO3)3 + Bi2S3 ⇌ La2S3 + Bi2(CO3)3
(C) CdSO4 + CaS ⇌ CdS + CaSO4
(D) BeF2 + HgI2 ⇌ BeI2 + HgF2
The reaction of XeF6 with a limited amount of quartz gives compound A. Then on reaction with an equivalent amount of XeO3, A gives B. The products A and B are, respectively
Which of the following reaction(s) do(es) NOT occur
(i) [NPCl2]3 + 6 NaF \(\rm \xrightarrow[reflux]{MeCN}\) [NPF2]3 + 6 NaCl
(ii) n PCl5 + n NH4Cl \(\rm \xrightarrow[reflux]{C_6H_5Cl}\) [NPCl2]n + 4 n HCl [n = 3, 4, 5]
(iii) n PF 5 + n NH 4 F \(\rm \xrightarrow[reflux]{C_6H_5Cl}\) [NPF 2 ] n + 4 n HF [n = 3, 4, 5]