All Exams Test series for 1 year @ ₹349 only
Question

Among 150 faculty members in an institute, 55 are connected with each other through Facebook and 85 are connected through WhatsApp. 30 faculty members do not have Facebook or WhatsApp accounts. The number of faculty members connected only through Facebook accounts is ______________.

The correct answer is

35

Understanding the Faculty Connectivity Problem

This problem involves using set theory concepts to determine the number of faculty members with only a specific type of social media account. We are given the total number of faculty members, the number connected via Facebook, the number via WhatsApp, and the number with neither account. We need to find the number connected only through Facebook.

Defining the Sets and Given Data

Let's define the sets involved:

  • Total number of faculty members, $|U| = 150$
  • Number of faculty members with Facebook accounts, $|F| = 55$
  • Number of faculty members with WhatsApp accounts, $|W| = 85$
  • Number of faculty members with neither account, $|(F \cup W)'| = 30$

We want to find the number of faculty members connected only through Facebook accounts, which can be represented as $|F \text{ only}|$.

Calculating Faculty Members with At Least One Account

The total number of faculty members is the sum of those with at least one account (Facebook or WhatsApp or both) and those with neither account. Using the principle of inclusion-exclusion for the total set:

\(|U| = |F \cup W| + |(F \cup W)'|\)

We can find the number of faculty members with at least one account:

\(|F \cup W| = |U| - |(F \cup W)'|\)

Substituting the given values:

\(|F \cup W| = 150 - 30\)

\(|F \cup W| = 120\)

So, 120 faculty members are connected through Facebook or WhatsApp or both.

Finding Faculty Members with Both Accounts

The formula for the union of two sets is:

\(|F \cup W| = |F| + |W| - |F \cap W|\)

Here, $|F \cap W|$ represents the number of faculty members connected through both Facebook and WhatsApp accounts.

We know $|F \cup W| = 120$, $|F| = 55$, and $|W| = 85$. Substituting these values into the formula:

\(120 = 55 + 85 - |F \cap W|\)

\(120 = 140 - |F \cap W|\)

Now, we can solve for $|F \cap W|$:

\(|F \cap W| = 140 - 120\)

\(|F \cap W| = 20\)

Therefore, 20 faculty members are connected through both Facebook and WhatsApp.

Calculating Faculty Members Connected Only Through Facebook

The number of faculty members connected only through Facebook is the total number of Facebook users minus those who are also connected through WhatsApp (since those are included in the total Facebook count).

\(|F \text{ only}| = |F| - |F \cap W|\)

We know $|F| = 55$ and $|F \cap W| = 20$. Substituting these values:

\(|F \text{ only}| = 55 - 20\)

\(|F \text{ only}| = 35\)

Thus, 35 faculty members are connected only through Facebook accounts.

Summary of Results

Category Number of Faculty Members
Total 150
Facebook (|F|) 55
WhatsApp (|W|) 85
Neither (|(F ∪ W)') 30
At least one (Facebook or WhatsApp) (|F ∪ W|) 120
Both (Facebook and WhatsApp) (|F ∩ W|) 20
Only Facebook (|F only|) 35
Only WhatsApp (|W only|) \(|W| - |F \cap W| = 85 - 20 = 65\)

The number of faculty members connected only through Facebook accounts is 35.

Revision Table: Key Set Theory Concepts

Concept Notation Explanation
Union \(A \cup B\) Elements in A OR B OR both.
Intersection \(A \cap B\) Elements in A AND B.
Complement \(A'\) or \(A^c\) Elements NOT in A (within the universal set).
Inclusion-Exclusion Principle (Two Sets) \(|A \cup B| = |A| + |B| - |A \cap B|\) Formula to find the size of the union of two sets.
Only A \(|A| - |A \cap B|\) Elements in A but not in B.

Additional Information: Visualizing with Venn Diagrams

While not required for the calculation, visualizing this problem with a Venn diagram can be helpful. Draw two overlapping circles, one for Facebook (F) and one for WhatsApp (W), within a rectangle representing the Universal Set (U). The overlapping area is the intersection (\(F \cap W\)). The area inside the F circle but outside the overlap is Only Facebook (\(F \text{ only}\)). The area inside the W circle but outside the overlap is Only WhatsApp (\(W \text{ only}\)). The area outside both circles but inside the rectangle is Neither (\((F \cup W)'\)).

  • The sum of the areas for Only F, Only W, and Both F&W equals \(|F \cup W|\).
  • The sum of Only F and Both F&W equals \(|F|\).
  • The sum of Only W and Both F&W equals \(|W|\).
  • The sum of Only F, Only W, Both F&W, and Neither equals \(|U|\).

Using our calculated values:

  • Both (F & W) = 20
  • Only F = 35 (calculated)
  • Only W = 65 (calculated as \(85 - 20\))
  • Neither = 30 (given)

Check the total: \(35 + 65 + 20 + 30 = 150\), which matches the total number of faculty members.

Was this answer helpful?

Important Questions from Numerical Reasoning

  1. X is 1 km northeast of Y. Y is 1 km southeast of Z. W is 1 km west of Z. P is 1 km south of W. Q is 1 km east of P. What is the distance between X and Q in km?

  2. Two numbers are, respectively, 28% and 25% less than a third number. What percent is the first number of the second number?
  3. A dealer sold three-forth (3/4th) of his articles at a gain of 20% and the remaining articles at the cost price. Find the gain earned by him in the whole transaction.

  4. 78, 65, 82, 69, 86, ?

  5. A traveller to the town reaches a crossroad. Upon asking residents A, B and C for directions to a certain destination, he gets the following responses

    A: turn left

    B: do not turn left

    C: go straight

    If only one among A, B and C is truthful, the traveller 

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App