If ⊕ ÷ ⊙ = 2; ⊕ ÷ Δ = 3; ⊙ + Δ = 5; Δ × ⊗ = 10, Then the value of (⊗ - ⊕)2, is
1
This problem requires us to solve a system of equations involving different symbols, then use the values found to evaluate a final mathematical expression. We are given four equations with four unknown symbols: $\oplus$, $\odot$, $\Delta$, and $\otimes$. Our goal is to find the value of $(\otimes - \oplus)^2$. We will solve for each symbol step-by-step.
Let's list the given equations clearly:
We will start by expressing some symbols in terms of others from the simpler equations.
$\frac{\oplus}{\odot} = 2$
This means $\oplus = 2 \times \odot$ (Equation A)
$\frac{\oplus}{\Delta} = 3$
This means $\oplus = 3 \times \Delta$ (Equation B)
Now, we can equate Equation A and Equation B since both are equal to $\oplus$:
$2 \times \odot = 3 \times \Delta$
From this, we can express $\odot$ in terms of $\Delta$:
$\odot = \frac{3}{2} \times \Delta$ (Equation C)
Next, we will use Equation (3) which relates $\odot$ and $\Delta$ directly:
$\odot + \Delta = 5$
Substitute the value of $\odot$ from Equation C into Equation (3):
$\frac{3}{2} \Delta + \Delta = 5$
Combine the terms with $\Delta$:
$\left(\frac{3}{2} + 1\right) \Delta = 5$
$\left(\frac{3}{2} + \frac{2}{2}\right) \Delta = 5$
$\frac{5}{2} \Delta = 5$
Now, solve for $\Delta$:
$\Delta = 5 \times \frac{2}{5}$
$\Delta = 2$
With the value of $\Delta$ found, we can now find the values of $\odot$, $\oplus$, and $\otimes$.
Using Equation C: $\odot = \frac{3}{2} \times \Delta$
$\odot = \frac{3}{2} \times 2$
$\odot = 3$
Using Equation B: $\oplus = 3 \times \Delta$
$\oplus = 3 \times 2$
$\oplus = 6$
(Alternatively, using Equation A: $\oplus = 2 \times \odot = 2 \times 3 = 6$, which confirms our value.)
Using Equation (4): $\Delta \times \otimes = 10$
Substitute the value of $\Delta$:
$2 \times \otimes = 10$
$\otimes = \frac{10}{2}$
$\otimes = 5$
Let's list the values we found for each symbol:
| Symbol | Value |
|---|---|
| $\oplus$ | 6 |
| $\odot$ | 3 |
| $\Delta$ | 2 |
| $\otimes$ | 5 |
The problem asks us to find the value of $(\otimes - \oplus)^2$.
Substitute the values of $\otimes = 5$ and $\oplus = 6$ into the expression:
$(\otimes - \oplus)^2 = (5 - 6)^2$
First, calculate the value inside the parentheses:
$5 - 6 = -1$
Now, square the result:
$(-1)^2 = (-1) \times (-1) = 1$
Therefore, the value of $(\otimes - \oplus)^2$ is 1.
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