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Question

If ⊕ ÷ ⊙ = 2; 

⊕ ÷ Δ = 3; 

⊙ + Δ = 5; 

Δ × ⊗ = 10,

Then the value of (⊗ - ⊕)2, is 

The correct answer is

1

Mathematical Expression Simplification

This problem requires us to solve a system of equations involving different symbols, then use the values found to evaluate a final mathematical expression. We are given four equations with four unknown symbols: $\oplus$, $\odot$, $\Delta$, and $\otimes$. Our goal is to find the value of $(\otimes - \oplus)^2$. We will solve for each symbol step-by-step.

Decoding the Given Equations

Let's list the given equations clearly:

  1. $\oplus \div \odot = 2$
  2. $\oplus \div \Delta = 3$
  3. $\odot + \Delta = 5$
  4. $\Delta \times \otimes = 10$

Solving for Each Symbol

We will start by expressing some symbols in terms of others from the simpler equations.

  • From Equation (1):

    $\frac{\oplus}{\odot} = 2$

    This means $\oplus = 2 \times \odot$ (Equation A)

  • From Equation (2):

    $\frac{\oplus}{\Delta} = 3$

    This means $\oplus = 3 \times \Delta$ (Equation B)

Now, we can equate Equation A and Equation B since both are equal to $\oplus$:

$2 \times \odot = 3 \times \Delta$

From this, we can express $\odot$ in terms of $\Delta$:

$\odot = \frac{3}{2} \times \Delta$ (Equation C)

Next, we will use Equation (3) which relates $\odot$ and $\Delta$ directly:

  • Using Equation (3):

    $\odot + \Delta = 5$

    Substitute the value of $\odot$ from Equation C into Equation (3):

    $\frac{3}{2} \Delta + \Delta = 5$

    Combine the terms with $\Delta$:

    $\left(\frac{3}{2} + 1\right) \Delta = 5$

    $\left(\frac{3}{2} + \frac{2}{2}\right) \Delta = 5$

    $\frac{5}{2} \Delta = 5$

    Now, solve for $\Delta$:

    $\Delta = 5 \times \frac{2}{5}$

    $\Delta = 2$

With the value of $\Delta$ found, we can now find the values of $\odot$, $\oplus$, and $\otimes$.

  • Finding $\odot$:

    Using Equation C: $\odot = \frac{3}{2} \times \Delta$

    $\odot = \frac{3}{2} \times 2$

    $\odot = 3$

  • Finding $\oplus$:

    Using Equation B: $\oplus = 3 \times \Delta$

    $\oplus = 3 \times 2$

    $\oplus = 6$

    (Alternatively, using Equation A: $\oplus = 2 \times \odot = 2 \times 3 = 6$, which confirms our value.)

  • Finding $\otimes$:

    Using Equation (4): $\Delta \times \otimes = 10$

    Substitute the value of $\Delta$:

    $2 \times \otimes = 10$

    $\otimes = \frac{10}{2}$

    $\otimes = 5$

Summary of Symbol Values

Let's list the values we found for each symbol:

Symbol Value
$\oplus$ 6
$\odot$ 3
$\Delta$ 2
$\otimes$ 5

Calculating the Final Expression

The problem asks us to find the value of $(\otimes - \oplus)^2$.

Substitute the values of $\otimes = 5$ and $\oplus = 6$ into the expression:

$(\otimes - \oplus)^2 = (5 - 6)^2$

First, calculate the value inside the parentheses:

$5 - 6 = -1$

Now, square the result:

$(-1)^2 = (-1) \times (-1) = 1$

Therefore, the value of $(\otimes - \oplus)^2$ is 1.

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Important Questions from Numerical Reasoning

  1. a, b, c are real numbers. The quadratic equation ax2 – bx + c = 0 has equal roots, which is β, then

  2. S, M, E and F are working in shifts in a team to finish a project. M works with twice the efficiency of others but for half as many days as E worked. S and M have 6 hour shifts in a day, whereas E and F have 12 hours shifts. What is the ratio of contribution of M to contribution of E in the project?

  3. If x>y>1, which of the following must be true?

    (i) In x > In y

    (ii) ex > ey

    (iii) y2 > x2

    (iv) cos x > cos y
  4. Michael lives 10 km away from where I live. Ahmed lives 5 km away and Susan lives 7 km away from where I live. Arun is farther away than Ahmed but closer than Susan from where I live. From the information provided here, what is one possible distance (in km) at which I live from Arun’s place?

  5. If IMHO = JNIP; IDK = JEL; and SO = TP, then IDC = ____.

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