Age of A : Age of B is 3 : 2. Ten years hence, the sum of their ages will be 80. What are their present ages?
36, 24
This question involves finding the present ages of two individuals, A and B, based on a given ratio of their ages and the sum of their ages after a certain number of years.
Let the present age of A be \(A_p\) and the present age of B be \(B_p\).
We are given the ratio of their present ages:
\(\frac{A_p}{B_p} = \frac{3}{2}\)
We can express their present ages in terms of a common variable, say \(x\). Let:
Next, we need to consider their ages after 10 years. Their ages will increase by 10 years.
We are also given that the sum of their ages after 10 years will be 80 years.
So, we can write the equation:
\((3x + 10) + (2x + 10) = 80\)
Now, let's solve this linear equation for \(x\):
\(3x + 10 + 2x + 10 = 80\)
Combine the like terms:
\((3x + 2x) + (10 + 10) = 80\)
\(5x + 20 = 80\)
Subtract 20 from both sides of the equation:
\(5x = 80 - 20\)
\(5x = 60\)
Divide both sides by 5 to find the value of \(x\):
\(x = \frac{60}{5}\)
\(x = 12\)
Now that we have the value of \(x\), we can find their present ages:
Let's check if these present ages satisfy the condition about the sum of their ages after 10 years.
Sum of their ages after 10 years \( = 46 + 34 = 80\) years.
This matches the information given in the problem, confirming our calculated present ages are correct.
| Person | Present Age (years) | Age After 10 Years (years) |
|---|---|---|
| A | 36 | \(36 + 10 = 46\) |
| B | 24 | \(24 + 10 = 34\) |
| Sum of Ages After 10 Years | \(46 + 34 = 80\) | |
The present ages of A and B are 36 years and 24 years, respectively.
| Concept | Explanation |
|---|---|
| Ratio | A comparison of two quantities by division. Here, \(3:2\) means A's age is \(3k\) and B's age is \(2k\) for some constant \(k\). |
| Setting up Variables | Representing unknown quantities (like present ages) using variables (like \(3x\) and \(2x\)). |
| Forming Equations | Translating the word problem into a mathematical equation based on the given information (sum of future ages). |
| Solving Linear Equations | Using algebraic techniques (combining like terms, isolating the variable) to find the value of the unknown variable. |
| Age after 'n' years | If present age is P, age after 'n' years is \(P + n\). |
Age problems are common in mathematics and quantitative aptitude tests. They often involve relationships between ages at different points in time (past, present, future).
Key strategies for solving age problems:
This specific problem used a ratio and a sum of future ages, leading to a single linear equation in one variable.
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