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Question

After leaving school, Hemant and Anurag walk towards the north for 1 km to reach a bus stop. From the bus stop, Hemant turns left and walks for 500 m. Then he turns towards his left and walks for 2 km to reach his home. From the bus stop, Anurag turns right and walks for 250 m. Then he turns right and walks for 1 km to reach his home. In which direction is Anurag's home from Hemant's home?

The correct answer is

North-East

Understanding the Directional Movement Problem

This question involves analyzing the paths taken by two individuals, Hemant and Anurag, after leaving school. They first walk together to a bus stop, and then diverge to their respective homes. We need to determine the direction of Anurag's home relative to Hemant's home.

Step-by-Step Path Analysis

Let's break down the movements of Hemant and Anurag from the bus stop, as the school-to-bus-stop path is common and serves as a starting point for their separate journeys.

Hemant's Path from the Bus Stop:

  • Starts at the Bus Stop.
  • Turns left and walks for $500 \text{ m}$. Assuming standard directions, 'left' from North is West. So, $0.5 \text{ km}$ West.
  • From there, he turns towards his left and walks for $2 \text{ km}$. If he was heading West, a left turn means turning South. So, $2 \text{ km}$ South.
  • Hemant reaches his home.

So, Hemant's home is located $0.5 \text{ km}$ West and $2 \text{ km}$ South of the Bus Stop.

Anurag's Path from the Bus Stop:

  • Starts at the Bus Stop.
  • Turns right and walks for $250 \text{ m}$. Assuming standard directions, 'right' from North is East. So, $0.25 \text{ km}$ East.
  • From there, he turns right and walks for $1 \text{ km}$. If he was heading East, a right turn means turning South. So, $1 \text{ km}$ South.
  • Anurag reaches his home.

So, Anurag's home is located $0.25 \text{ km}$ East and $1 \text{ km}$ South of the Bus Stop.

Determining Final Positions Relative to Bus Stop

Let's summarize the final positions of their homes with respect to the Bus Stop:

Individual Direction (X-axis) Distance (X-axis) Direction (Y-axis) Distance (Y-axis)
Hemant's Home West $0.5 \text{ km}$ South $2 \text{ km}$
Anurag's Home East $0.25 \text{ km}$ South $1 \text{ km}$

Finding the Direction of Anurag's Home from Hemant's Home

To find the direction of Anurag's home from Hemant's home, imagine standing at Hemant's home and looking towards Anurag's home. We need to determine the relative displacement from Hemant's position to Anurag's position.

  • Horizontal Displacement: Hemant is $0.5 \text{ km}$ West of the Bus Stop. Anurag is $0.25 \text{ km}$ East of the Bus Stop. To get from Hemant's West position to Anurag's East position, you need to move East. The total eastward distance is $0.5 \text{ km} (\text{to reach Bus Stop line}) + 0.25 \text{ km} (\text{from Bus Stop line to Anurag}) = 0.75 \text{ km}$ East.
  • Vertical Displacement: Hemant is $2 \text{ km}$ South of the Bus Stop. Anurag is $1 \text{ km}$ South of the Bus Stop. To get from Hemant's position ($2 \text{ km}$ South) to Anurag's position ($1 \text{ km}$ South), you need to move North. The total northward distance is $2 \text{ km} - 1 \text{ km} = 1 \text{ km}$ North.

From Hemant's home, Anurag's home is $0.75 \text{ km}$ East and $1 \text{ km}$ North.

A position that is both North and East relative to a starting point is in the North-East direction.

Conclusion on Direction

Based on the relative positions, Anurag's home is to the North-East of Hemant's home.

Revision Table: Analyzing Hemant and Anurag's Journeys

Reference Point Person From Bus Stop (Horizontal) From Bus Stop (Vertical)
Bus Stop Hemant $0.5 \text{ km}$ West $2 \text{ km}$ South
Anurag $0.25 \text{ km}$ East $1 \text{ km}$ South
Hemant's Home Anurag's Home (Relative) $0.75 \text{ km}$ East $1 \text{ km}$ North

Additional Information on Directional Reasoning

Directional reasoning questions often require visualizing movements and calculating final positions based on sequences of turns and distances. It's helpful to:

  • Establish a clear starting point and positive/negative directions (e.g., East is positive X, North is positive Y).
  • Break down complex paths into simpler segments (e.g., North, South, East, West).
  • Calculate the net displacement in each primary direction (North-South and East-West).
  • Combine the net displacements to find the final position relative to the starting point.
  • When finding the direction of point B from point A, calculate the displacement from A to B. If the displacement is, for instance, 'X units East' and 'Y units North', the direction is North-East.
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Important Questions from Direction and Distance Turns

  1. Shweta starts walking from her office and walks 150 m towards the south, then she turns right and walks 80 m, and then she turns left and walks 60 m. She finally turns left and walks 280 m to reach a bank. What is the shortest distance between her office and the bank?

  2. Starting from her home, a woman walks 10 km towards the west. She turns left and walks 25 km. Again she turns left and walks 10 km. After that, she again turns left and walks 5 km. How far is she from her house now?

    A. 35

    B. 20

    C. 25

    D. 40

  3. A man travels 15 km towards the east, then turns right and travels 20 km. He then turns left and travels 30 km. Finally, he takes a right turn and covers 40 km. The shortest distance between the starting point and the destination is:

  4. A man starts from point ‘O’, travels 20 km towards East to reach point ‘A’, turns right and travels 10 km to reach point 'B', turns right and travels 9 km to reach point 'C', turns right and travels 5 km to reach point 'D', turns left and travels 12 km to reach point 'E' and then turns right and travels 6 km to reach point 'F'.

    In which direction is the man facing now?

  5. Lalit walks 9 km east, turns left and walks another 8 km. He again takes a left and walks another 3 km. How far and in which direction is he now from his starting point?

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