Above conversion is carried out using
The given reaction involves the conversion of a bromide to an alcohol. This can be achieved in two main steps as follows:
- The first step involves the elimination reaction using alcoholic KOH. This leads to the formation of an alkene by removing the bromine atom and a hydrogen atom from the carbon adjacent to it.
- The second step is the hydroboration-oxidation of the alkene. This reaction proceeds via the addition of borane \( (BH_3) \) followed by oxidation with hydrogen peroxide in the presence of a base.
Let's discuss each step in detail:
- KOH (alc.): The alcoholic solution of KOH favors elimination (E2 mechanism) over substitution, thus converting the bromo-compound into an alkene by removing HBr.
- Hydroboration-Oxidation: This two-step reaction adds water across the double bond in a syn-addition manner, yielding the alcohol. It proceeds through the formation of trialkylborane followed by oxidation to produce the alcohol.
Therefore, the correct answer is:
(I) KOH (alc.), (II) Hydroboration-oxidation
This choice efficiently converts the bromoalkane to the corresponding alcohol, matching the transformation depicted in the figure.
Important Questions from Chemistry (CUET PG) Mixed
The final product (P) is
Consider the following statements with respect to citral
(A). Geranial and Neral are geometrical isomers of citral.
(B). It forms geranic acid on heating with potassium hydrogen sulphate.
(C). It gives 6-methylhept-5-en-2-one on treating with potassium carbonate.
(D). On oxidation with silver oxide it yields Laevulic acid.
Choose the correct answer from the options given below:Which correct sequence of reactions are applied to achieve the following transformation?
The final product (D) in the above conversion is
The major product (P) in the following transformation is
