A truck driver drove 60 km/h for three hours. Then he stopped for one hour and did not go anywhere. Then, he drove four more hours at 60 km/h. What was the driver's average speed (in km/h)?
52.5
The question asks us to find the average speed of a truck driver over a journey that includes different phases: driving at a constant speed and stopping for a period. To calculate the average speed, we need to use the formula:
\(\text{Average Speed} = \frac{\text{Total Distance Traveled}}{\text{Total Time Taken}}\)
It's important to account for all parts of the journey in both the total distance and the total time.
Let's break down the truck driver's journey into segments to find the total distance and total time.
Total Distance Traveled = Distance in Segment 1 + Distance in Segment 2 + Distance in Segment 3
Total Distance = 180 km + 0 km + 240 km = 420 km.
The total time taken for the entire journey is the sum of the durations of all segments.
Total Time Taken = Time in Segment 1 + Time in Segment 2 + Time in Segment 3
Total Time = 3 hours + 1 hour + 4 hours = 8 hours.
Now we can use the total distance and total time in the average speed formula.
\(\text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}}\)
\(\text{Average Speed} = \frac{420 \text{ km}}{8 \text{ hours}}\)
\(\text{Average Speed} = 52.5 \text{ km/h}\)
The truck driver's average speed for the entire journey was 52.5 km/h.
| Segment | Speed (km/h) | Time (hours) | Distance (km) |
|---|---|---|---|
| 1 | 60 | 3 | 180 |
| 2 (Stop) | 0 | 1 | 0 |
| 3 | 60 | 4 | 240 |
| Total | - | 8 | 420 |
Average Speed = \(\frac{\text{Total Distance}}{\text{Total Time}} = \frac{420}{8} = 52.5 \text{ km/h}\)
| Concept | Formula | Notes |
|---|---|---|
| Speed | \(\text{Speed} = \frac{\text{Distance}}{\text{Time}}\) | Rate of motion, scalar quantity |
| Distance | \(\text{Distance} = \text{Speed} \times \text{Time}\) | How far an object traveled |
| Time | \(\text{Time} = \frac{\text{Distance}}{\text{Speed}}\) | Duration of motion |
| Average Speed | \(\text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}}\) | Applies over an entire journey |
| Velocity | \(\text{Velocity} = \frac{\text{Displacement}}{\text{Time}}\) | Speed with direction, vector quantity |
It's helpful to understand the difference between average speed and instantaneous speed.
In this truck driver problem, even though the driving speed was constant at 60 km/h when the truck was moving, the average speed over the entire 8-hour period was lower (52.5 km/h) because the total time included a period where no distance was covered.
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X and Y travel a distance of 90 km each such that the speed of Y is greater than that of X. The sum of their speeds is 100 km/h and the total time taken by both is 3 hours 45 minutes. The ratio of the speed of X to that of Y is:
If a man travels at \(\frac{1}{x}\) km/h on a journey and returns at \(\rm \frac{1}{x^2}\) km/h, then his average speed for the journey is: